The solubility of a substance can be measured in grams/liter. In a chemistry lab, Justin and Ellie are working with a substance that has a solubility of 12 grams/liter. This ratio means that 12 grams of the substance can dissolve in one liter of water. It would require liters of water to dissolve 36 grams of the substance.
The Correct Answer and Explanation is:
To find out how many liters of water are needed to dissolve 36 grams of the substance, we can use the given solubility ratio of 12 grams per liter.
Step-by-Step Solution:
We know that 12 grams of the substance dissolves in 1 liter of water. This means:12 grams1 liter=12 grams/liter\frac{12 \, \text{grams}}{1 \, \text{liter}} = 12 \, \text{grams/liter}1liter12grams=12grams/liter
Now, we need to find how many liters of water are required to dissolve 36 grams of the substance. We set up a proportion to solve for the unknown number of liters:12 grams1 liter=36 gramsx liters\frac{12 \, \text{grams}}{1 \, \text{liter}} = \frac{36 \, \text{grams}}{x \, \text{liters}}1liter12grams=xliters36grams
Where xxx represents the number of liters required to dissolve 36 grams of the substance. To solve for xxx, we can cross-multiply:12⋅x=36⋅112 \cdot x = 36 \cdot 112⋅x=36⋅1
This simplifies to:12x=3612x = 3612x=36
Next, divide both sides of the equation by 12:x=3612=3x = \frac{36}{12} = 3x=1236=3
Final Answer:
It would require 3 liters of water to dissolve 36 grams of the substance.
Explanation:
The solubility is the amount of substance that can dissolve in a given amount of solvent, usually expressed as grams per liter. Since the solubility is 12 grams per liter, this means that for every liter of water, 12 grams of the substance can dissolve. To dissolve 36 grams of the substance, we need 3 liters of water, which is calculated by dividing the total amount of substance (36 grams) by the solubility (12 grams per liter).
