The Correct Answer and Explanation is:
Of course. Here is the completed table with the limit infimum and limit supremum for each sequence, followed by a detailed justification.
| xₙ | lim inf(xₙ) | lim sup(xₙ) |
| xₙ = 3 − (−1)ⁿ | 2 | 4 |
| xₙ = cos(nπ/2) | -1 | 1 |
| xₙ = (√(1+n²))/(2n-5) | 1/2 | 1/2 |
| xₙ = yₙ/n |
