How many chlorine atoms would there be in the 145 grams of copper (II) chlorate Cu(ClO3)2

How many chlorine atoms would there be in the 145 grams of copper (II) chlorate Cu(ClO3)2? Hint: The molar mass of copper (II) chlorate is 230.45 g/mol.

The Correct Answer and Explanation is:

To find how many chlorine atoms are present in 145 grams of copper (II) chlorate (Cu(ClO₃)₂), we will use the concept of moles, molar mass, and Avogadro’s number.

Step 1: Calculate the number of moles of Cu(ClO₃)₂

The molar mass of copper (II) chlorate is given as 230.45 g/mol. To find the number of moles of Cu(ClO₃)₂ in 145 grams, we divide the mass by the molar mass.Number of moles of Cu(ClO₃)₂=Mass of Cu(ClO₃)₂Molar mass of Cu(ClO₃)₂=145 g230.45 g/mol≈0.629 mol\text{Number of moles of Cu(ClO₃)₂} = \frac{\text{Mass of Cu(ClO₃)₂}}{\text{Molar mass of Cu(ClO₃)₂}} = \frac{145 \, \text{g}}{230.45 \, \text{g/mol}} \approx 0.629 \, \text{mol}Number of moles of Cu(ClO₃)₂=Molar mass of Cu(ClO₃)₂Mass of Cu(ClO₃)₂​=230.45g/mol145g​≈0.629mol

Step 2: Calculate the number of chlorine atoms

In one formula unit of Cu(ClO₃)₂, there are 2 chlorine (Cl) atoms. Therefore, the total number of chlorine atoms in 0.629 moles of Cu(ClO₃)₂ is:Number of chlorine atoms=Number of moles of Cu(ClO₃)₂×Avogadro’s number×Number of chlorine atoms per formula unit\text{Number of chlorine atoms} = \text{Number of moles of Cu(ClO₃)₂} \times \text{Avogadro’s number} \times \text{Number of chlorine atoms per formula unit}Number of chlorine atoms=Number of moles of Cu(ClO₃)₂×Avogadro’s number×Number of chlorine atoms per formula unitNumber of chlorine atoms=0.629 mol×6.022×1023 atoms/mol×2\text{Number of chlorine atoms} = 0.629 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \times 2Number of chlorine atoms=0.629mol×6.022×1023atoms/mol×2Number of chlorine atoms≈7.57×1023 atoms\text{Number of chlorine atoms} \approx 7.57 \times 10^{23} \, \text{atoms}Number of chlorine atoms≈7.57×1023atoms

Final Answer:

There are approximately 7.57 × 10²³ chlorine atoms in 145 grams of copper (II) chlorate (Cu(ClO₃)₂).

This approach makes use of moles to convert mass to the number of particles, which is a crucial concept in stoichiometry for understanding how many atoms or molecules are in a given mass of a substance.

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