A gallon of water weighs 8.34 pounds. The Patel family has a round, 12-foot diameter, above-ground pool. How much weight is added to the pool when it is filled with 3,110 gallons of water?
The Correct Answer and Explanation is:
To calculate the weight added to the pool when it is filled with 3,110 gallons of water, we can use the weight of 1 gallon of water, which is 8.34 pounds.
Step 1: Determine the total weight of water
We know that each gallon of water weighs 8.34 pounds, so we multiply the number of gallons of water by the weight of each gallon:Weight of water=3,110 gallons×8.34 pounds per gallon\text{Weight of water} = 3,110 \, \text{gallons} \times 8.34 \, \text{pounds per gallon}Weight of water=3,110gallons×8.34pounds per gallonWeight of water=25,917.4 pounds\text{Weight of water} = 25,917.4 \, \text{pounds}Weight of water=25,917.4pounds
Step 2: Conclusion
The weight added to the pool when it is filled with 3,110 gallons of water is 25,917.4 pounds.
This weight comes from the volume of water in the pool, which is determined by how many gallons the pool holds. Given that 1 gallon weighs 8.34 pounds, multiplying by the total number of gallons gives the total weight.
In real-world scenarios, knowing the weight of the water is essential, as it affects both the structural integrity of the pool and the foundation it sits on.
