An element x has 13 protons 13 electrons and 14 neutrons what is the type of ion formed by x
The Correct Answer and Explanation is:
The element described has 13 protons, 13 electrons, and 14 neutrons. This gives us the following information:
- The atomic number of the element is 13, as the number of protons defines the element. This corresponds to the element aluminum (Al).
- The number of electrons is the same as the number of protons, meaning the atom is neutral.
- The element has 14 neutrons, which suggests that this is an isotope of aluminum with a mass number of 27 (13 protons + 14 neutrons).
Now, for the ion formation:
- The number of electrons determines whether an atom is neutral or has a charge. Since aluminum typically forms positive ions (cations), the element will likely lose electrons to form a cation when it becomes ionized.
- Aluminum commonly forms a +3 charge by losing 3 electrons (since it has 3 electrons in its outer shell that it can lose to achieve a stable electron configuration). This means the element Al will form a +3 ion (Al³⁺).
Conclusion:
The ion formed by X is an Al³⁺ (aluminum ion), which has a +3 charge. This is because aluminum tends to lose three electrons to achieve a stable electron configuration similar to the nearest noble gas, neon (Ne). The atom becomes a cation (positively charged ion) after this electron loss.
