What is the formula for copper(II) phosphate? Capitalization and punctuation count. Formula: Cu3(PO4)2. How many atoms of phosphorus are in 3.70 mol of copper(II) phosphate? Number of P atoms: 229.4.
The Correct Answer and Explanation is:
The formula for copper(II) phosphate is Cu₃(PO₄)₂.
To find the number of phosphorus (P) atoms in 3.70 mol of copper(II) phosphate, follow these steps:
- Understanding the formula:
The chemical formula Cu₃(PO₄)₂ indicates that each molecule of copper(II) phosphate contains 2 phosphate ions (PO₄²⁻), and each phosphate ion contains 1 phosphorus (P) atom. Therefore, for each formula unit of copper(II) phosphate, there are 2 phosphorus atoms. - Calculating the number of molecules in 3.70 mol of Cu₃(PO₄)₂:
One mole of any substance contains Avogadro’s number of molecules, which is approximately 6.022×10236.022 \times 10^{23}6.022×1023 molecules. So, 3.70 mol of copper(II) phosphate will contain: 3.70 mol×(6.022×1023 molecules/mol)=2.23×1024 molecules.3.70 \, \text{mol} \times (6.022 \times 10^{23} \, \text{molecules/mol}) = 2.23 \times 10^{24} \, \text{molecules}.3.70mol×(6.022×1023molecules/mol)=2.23×1024molecules. - Finding the total number of phosphorus atoms:
Since each molecule of copper(II) phosphate contains 2 phosphorus atoms, the total number of phosphorus atoms in 3.70 mol is: 2.23×1024 molecules×2 P atoms/molecule=4.46×1024 P atoms.2.23 \times 10^{24} \, \text{molecules} \times 2 \, \text{P atoms/molecule} = 4.46 \times 10^{24} \, \text{P atoms}.2.23×1024molecules×2P atoms/molecule=4.46×1024P atoms. - Adjusting for molar mass:
In terms of moles, the number of phosphorus atoms in 3.70 mol of copper(II) phosphate is 2 times the moles of the compound, as there are 2 phosphorus atoms per formula unit of Cu₃(PO₄)₂: 3.70 mol×2 P atoms/mol=7.40 mol of P atoms.3.70 \, \text{mol} \times 2 \, \text{P atoms/mol} = 7.40 \, \text{mol of P atoms}.3.70mol×2P atoms/mol=7.40mol of P atoms.
Finally, to get the number of phosphorus atoms in terms of mass or moles, we use these basic relations, where each mole of P atoms equals Avogadro’s number. In conclusion, 3.70 mol of Cu₃(PO₄)₂ contains 7.40 mol of phosphorus atoms.
