What is the oxidation state of Cl in each ion

What is the oxidation state of Cl in each ion? a. ClO- b. ClO2- c. ClO3- d. ClO4-

The Correct Answer and Explanation is:

Let’s go through the oxidation states of chlorine in each ion one by one:

a. ClO⁻ (Hypochlorite ion)

In the hypochlorite ion (ClO⁻), oxygen has an oxidation state of -2. Since the ion has an overall charge of -1, the sum of the oxidation states of chlorine and oxygen must equal -1.

  • Let the oxidation state of chlorine be x.
  • The total charge equation will be:
    x + (-2) = -1
    x – 2 = -1
    x = +1

So, the oxidation state of chlorine in ClO⁻ is +1.

b. ClO₂⁻ (Chlorite ion)

In the chlorite ion (ClO₂⁻), oxygen has an oxidation state of -2. With a charge of -1, the sum of the oxidation states of chlorine and the two oxygens must equal -1.

  • Let the oxidation state of chlorine be x.
  • The total charge equation will be:
    x + 2(-2) = -1
    x – 4 = -1
    x = +3

So, the oxidation state of chlorine in ClO₂⁻ is +3.

c. ClO₃⁻ (Chlorate ion)

In the chlorate ion (ClO₃⁻), oxygen has an oxidation state of -2. With a charge of -1, the sum of the oxidation states of chlorine and the three oxygens must equal -1.

  • Let the oxidation state of chlorine be x.
  • The total charge equation will be:
    x + 3(-2) = -1
    x – 6 = -1
    x = +5

So, the oxidation state of chlorine in ClO₃⁻ is +5.

d. ClO₄⁻ (Perchlorate ion)

In the perchlorate ion (ClO₄⁻), oxygen again has an oxidation state of -2. With a charge of -1, the sum of the oxidation states of chlorine and the four oxygens must equal -1.

  • Let the oxidation state of chlorine be x.
  • The total charge equation will be:
    x + 4(-2) = -1
    x – 8 = -1
    x = +7

So, the oxidation state of chlorine in ClO₄⁻ is +7.

Summary:

  • a. ClO⁻: Oxidation state of Cl is +1.
  • b. ClO₂⁻: Oxidation state of Cl is +3.
  • c. ClO₃⁻: Oxidation state of Cl is +5.
  • d. ClO₄⁻: Oxidation state of Cl is +7.

Each of these species has chlorine in different oxidation states based on the number of oxygen atoms it is bonded to, which influences the overall charge distribution.

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