Determine the molarity for 0.2074 g of calcium hydroxide, Ca(OH)2, in 40.00 mL of solution. If you know the molar mass of H=1, O=16, and Ca=40 g/mol.
The Correct Answer and Explanation is:
To calculate the molarity of calcium hydroxide (Ca(OH)2) in a solution, follow these steps:
Step 1: Find the molar mass of Ca(OH)2.
The formula for calcium hydroxide is Ca(OH)2. We can calculate its molar mass by adding the atomic masses of all the atoms in the compound:
- Molar mass of Ca = 40 g/mol
- Molar mass of O = 16 g/mol
- Molar mass of H = 1 g/mol
For one molecule of Ca(OH)2:
- Ca = 1 × 40 g/mol = 40 g/mol
- O = 2 × 16 g/mol = 32 g/mol
- H = 2 × 1 g/mol = 2 g/mol
The total molar mass of Ca(OH)2 is:
40+32+2=74 g/mol40 + 32 + 2 = 74 \, \text{g/mol}40+32+2=74g/mol
Step 2: Convert the mass of Ca(OH)2 to moles.
The given mass of Ca(OH)2 is 0.2074 g. To find the number of moles of Ca(OH)2, use the formula: moles=massmolar mass\text{moles} = \frac{\text{mass}}{\text{molar mass}}moles=molar massmass
Substituting the known values: moles of Ca(OH)2=0.2074 g74 g/mol=0.00280 mol\text{moles of Ca(OH)2} = \frac{0.2074 \, \text{g}}{74 \, \text{g/mol}} = 0.00280 \, \text{mol}moles of Ca(OH)2=74g/mol0.2074g=0.00280mol
Step 3: Convert the volume of the solution to liters.
The volume of the solution is given as 40.00 mL. Since molarity is defined in terms of liters of solution, convert milliliters to liters: 40.00 mL=40.00 mL×1 L1000 mL=0.04000 L40.00 \, \text{mL} = 40.00 \, \text{mL} \times \frac{1 \, \text{L}}{1000 \, \text{mL}} = 0.04000 \, \text{L}40.00mL=40.00mL×1000mL1L=0.04000L
Step 4: Calculate the molarity.
Molarity (M) is defined as the number of moles of solute per liter of solution. Using the formula: M=moles of solutevolume of solution in litersM = \frac{\text{moles of solute}}{\text{volume of solution in liters}}M=volume of solution in litersmoles of solute
Substitute the values: M=0.00280 mol0.04000 L=0.0700 MM = \frac{0.00280 \, \text{mol}}{0.04000 \, \text{L}} = 0.0700 \, \text{M}M=0.04000L0.00280mol=0.0700M
Final Answer:
The molarity of the Ca(OH)2 solution is 0.0700 M.
Explanation:
The molarity tells us the concentration of the Ca(OH)2 solution in moles per liter. By calculating the moles of Ca(OH)2 from its mass and then dividing by the volume of the solution, we determine that the concentration is 0.0700 M.
