what is the molar mass of Barium Flouride
The correct answer and explanation is:
The molar mass of barium fluoride (BaF₂) can be calculated by adding the atomic masses of barium (Ba) and fluorine (F) from the periodic table.
- Atomic Mass of Barium (Ba): The atomic mass of barium is approximately 137.33 grams per mole (g/mol).
- Atomic Mass of Fluorine (F): The atomic mass of fluorine is approximately 18.998 grams per mole (g/mol).
Since there are two fluorine atoms in barium fluoride (BaF₂), the contribution from fluorine will be doubled.
Calculation:
- Barium: 1 atom × 137.33 g/mol = 137.33 g/mol
- Fluorine: 2 atoms × 18.998 g/mol = 37.996 g/mol
Now, add these two values together:
137.33 g/mol+37.996 g/mol=175.326 g/mol137.33 \, \text{g/mol} + 37.996 \, \text{g/mol} = 175.326 \, \text{g/mol}
Therefore, the molar mass of BaF₂ is 175.33 g/mol (rounded to two decimal places).
Explanation:
The molar mass of a compound represents the mass of one mole of that compound, expressed in grams per mole. To determine it, you sum the atomic masses of all the elements in the compound, taking into account the number of atoms of each element. This value is important for stoichiometric calculations, where you need to convert between grams and moles in chemical reactions.
For barium fluoride (BaF₂), the molar mass is directly linked to the elements involved. Barium is a metal in Group 2 of the periodic table, and its relatively high atomic mass is a major contributor to the molar mass of BaF₂. Fluorine, a halogen, is much lighter, but since there are two atoms of fluorine in each formula unit, their combined mass still significantly impacts the overall molar mass.
Knowing the molar mass of BaF₂ helps in determining how much of the compound is needed in reactions involving stoichiometric ratios, as well as in determining the mass of BaF₂ when a certain number of moles are present.