3.0 ml of cyclopentadiene to grams to moles
The Correct Answer and Explanation is:
To convert 3.0 mL of cyclopentadiene (C₅H₆) into grams and then moles, follow these steps:
Step 1: Convert volume to mass
First, you need to convert the volume of cyclopentadiene to grams. To do this, you will need the density of cyclopentadiene, which is typically 0.802 g/mL.
Given:
- Volume = 3.0 mL
- Density = 0.802 g/mL
Use the formula:Mass=Density×Volume\text{Mass} = \text{Density} \times \text{Volume}Mass=Density×VolumeMass=0.802 g/mL×3.0 mL=2.406 g\text{Mass} = 0.802 \, \text{g/mL} \times 3.0 \, \text{mL} = 2.406 \, \text{g}Mass=0.802g/mL×3.0mL=2.406g
So, the mass of 3.0 mL of cyclopentadiene is 2.406 grams.
Step 2: Convert grams to moles
Next, convert the mass of cyclopentadiene (C₅H₆) to moles. To do this, you need the molar mass of cyclopentadiene. The molar mass is the sum of the atomic masses of its constituent atoms:
- Carbon (C) = 12.01 g/mol
- Hydrogen (H) = 1.008 g/mol
Cyclopentadiene has 5 carbon atoms and 6 hydrogen atoms, so the molar mass is:Molar Mass=(5×12.01)+(6×1.008)=60.05+6.048=66.098 g/mol\text{Molar Mass} = (5 \times 12.01) + (6 \times 1.008) = 60.05 + 6.048 = 66.098 \, \text{g/mol}Molar Mass=(5×12.01)+(6×1.008)=60.05+6.048=66.098g/mol
Now, use the formula for converting grams to moles:Moles=MassMolar Mass\text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}}Moles=Molar MassMassMoles=2.406 g66.098 g/mol=0.0364 mol\text{Moles} = \frac{2.406 \, \text{g}}{66.098 \, \text{g/mol}} = 0.0364 \, \text{mol}Moles=66.098g/mol2.406g=0.0364mol
Final Answer:
- The mass of 3.0 mL of cyclopentadiene is 2.406 grams.
- The number of moles in 3.0 mL of cyclopentadiene is 0.0364 moles.
By following these steps, you can easily convert the volume of any liquid substance into moles, provided you have the density and molar mass.
