The element has the electron configuration [Xe]4f^145d^106s^2.
The Correct Answer and Explanation is:
The electron configuration [Xe] 4f¹⁴ 5d¹⁰ 6s² corresponds to the element Platinum (Pt), which has an atomic number of 78.
Explanation:
The notation [Xe] represents the electron configuration of Xenon, which is the noble gas with an atomic number of 54. This shorthand means that the electrons up to Xenon (in the 1s to 4p orbitals) are filled, and we need to focus on the remaining electrons. After Xenon, the electrons go into the 4f, 5d, and 6s orbitals.
- 4f¹⁴: This indicates that there are 14 electrons in the 4f orbital, which are characteristic of the lanthanide series elements.
- 5d¹⁰: This indicates that there are 10 electrons in the 5d orbital, a characteristic of transition metals.
- 6s²: This indicates that there are 2 electrons in the 6s orbital, the outermost shell for this element.
The atomic number of Platinum is 78 because when we count the total number of electrons in the configuration:
- Xenon (54 electrons)
- 14 electrons in the 4f orbital
- 10 electrons in the 5d orbital
- 2 electrons in the 6s orbital
The sum gives us 78 electrons, which is the atomic number of Platinum.
Platinum is a precious metal with a wide range of uses, including in jewelry, catalysis, and in various chemical reactions due to its ability to form stable complexes. It is a part of the transition metals and exhibits relatively high density and melting point due to the filled d-orbitals and its position in the periodic table.
