Calculate :Molarity of HNO3 solution contain 15g HNO3 in0.2 L solution.
The Correct Answer and Explanation is:
To calculate the molarity of the HNO3 solution, we need to follow a few steps:
Step 1: Determine the molar mass of HNO3
The molecular formula of nitric acid (HNO3) consists of:
- 1 hydrogen (H)
- 1 nitrogen (N)
- 3 oxygen atoms (O)
The atomic masses of the elements are:
- H = 1.008 g/mol
- N = 14.01 g/mol
- O = 16.00 g/mol
So, the molar mass of HNO3 is:Molar mass=(1.008 g/mol)+(14.01 g/mol)+(3×16.00 g/mol)=1.008+14.01+48.00=63.018 g/molMolar \, mass = (1.008 \, g/mol) + (14.01 \, g/mol) + (3 \times 16.00 \, g/mol) = 1.008 + 14.01 + 48.00 = 63.018 \, g/molMolarmass=(1.008g/mol)+(14.01g/mol)+(3×16.00g/mol)=1.008+14.01+48.00=63.018g/mol
Step 2: Calculate the number of moles of HNO3
Now, we need to convert the mass of HNO3 (15g) into moles using the formula:moles=massmolar massmoles = \frac{mass}{molar \, mass}moles=molarmassmassmoles=15 g63.018 g/mol=0.2387 molmoles = \frac{15 \, g}{63.018 \, g/mol} = 0.2387 \, molmoles=63.018g/mol15g=0.2387mol
Step 3: Calculate the molarity of the solution
Molarity (M) is defined as the number of moles of solute per liter of solution. The volume of the solution is given as 0.2 L. Using the formula for molarity:Molarity=molesvolume (in L)Molarity = \frac{moles}{volume \, (in \, L)}Molarity=volume(inL)molesMolarity=0.2387 mol0.2 L=1.1935 MMolarity = \frac{0.2387 \, mol}{0.2 \, L} = 1.1935 \, MMolarity=0.2L0.2387mol=1.1935M
Final Answer:
The molarity of the HNO3 solution is approximately 1.19 M.
Explanation:
- First, we calculated the molar mass of HNO3.
- Then, we used the given mass of HNO3 (15g) and the molar mass to find the number of moles.
- Finally, we used the volume of the solution (0.2 L) to determine the molarity.
This calculation helps determine how concentrated the HNO3 solution is in terms of the number of moles of HNO3 present in each liter of solution.
