Determine the egg’s altitude at 15 seconds.
-109.80 feet
cannot be determined
15.17 feet
O feet
The correct answer and explanation is:
To determine the altitude of the egg at 15 seconds, the correct answer would depend on the context of the egg’s motion. If this is part of a physics problem involving the motion of an egg, the altitude typically refers to the position of the egg at a specific time, which can be calculated using kinematic equations for vertical motion.
For example, if the egg was thrown upwards with an initial velocity, its altitude could be determined by the following kinematic equation: y=y0+v0t−12gt2y = y_0 + v_0t – \frac{1}{2}gt^2
Where:
- yy is the altitude at time tt,
- y0y_0 is the initial altitude (which could be 0 if it starts from ground level),
- v0v_0 is the initial velocity of the egg,
- tt is the time (15 seconds in this case),
- gg is the acceleration due to gravity (approximately 9.8 m/s² or 32.2 ft/s²).
If the problem provides more specific details, such as the initial velocity or height, this equation can be used to calculate the altitude at 15 seconds. In the absence of such details, the answer could not be determined.
Now, if the egg was dropped (and assuming zero initial velocity), the equation would simplify to: y=y0−12gt2y = y_0 – \frac{1}{2}gt^2
Depending on the initial conditions of the problem, this would help calculate the altitude after 15 seconds. However, with no specific data given, the correct choice would likely be “cannot be determined.”