How many bits do we need in order to represent the first 15 numbers

How many bits do we need in order to represent the first 15 numbers? How about the first 16, 25 or n numbers?

The Correct answer and Explanation is:

To determine how many bits are required to represent a certain range of numbers, we need to understand the relationship between bits and numerical representation in binary format. In binary, each bit can have two possible values: 0 or 1. Therefore, the number of unique values that can be represented by ( b ) bits is given by the formula:

[
\text{Unique values} = 2^b
]

1. First 15 Numbers

The first 15 numbers are typically considered to be the integers from 0 to 14. To find the number of bits required to represent these numbers, we need to find the smallest ( b ) such that:

[
2^b \geq 15
]

Calculating for ( b ):

  • ( 2^0 = 1 ) (1 value, not enough)
  • ( 2^1 = 2 ) (2 values, not enough)
  • ( 2^2 = 4 ) (4 values, not enough)
  • ( 2^3 = 8 ) (8 values, not enough)
  • ( 2^4 = 16 ) (16 values, sufficient)

Thus, we need 4 bits to represent the first 15 numbers.

2. First 16 Numbers

For the first 16 numbers (0 to 15), we follow a similar process:

[
2^b \geq 16
]

Here, ( 2^4 = 16 ) is sufficient, so 4 bits are also required for the first 16 numbers.

3. First 25 Numbers

For the first 25 numbers (0 to 24):

[
2^b \geq 25
]

Calculating:

  • ( 2^4 = 16 ) (not enough)
  • ( 2^5 = 32 ) (sufficient)

Therefore, we need 5 bits to represent the first 25 numbers.

4. General Case for ( n ) Numbers

For any ( n ) numbers, where we want to represent numbers from 0 to ( n-1 ), we determine ( b ) as follows:

[
2^b \geq n
]

Thus, the number of bits required can be expressed as:

[
b = \lceil \log_2(n) \rceil
]

Where ( \lceil x \rceil ) is the ceiling function, which rounds up to the nearest integer. This means you will need enough bits to represent all numbers up to ( n-1 ), ensuring that you have sufficient unique combinations of 0s and 1s to cover the range.

In summary:

  • For the first 15 numbers: 4 bits
  • For the first 16 numbers: 4 bits
  • For the first 25 numbers: 5 bits
  • For ( n ) numbers: ( b = \lceil \log_2(n) \rceil ) bits.
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