Write the molecular orbital configuration of Be2.

Write the molecular orbital configuration of Be2. Calculate its bond order and predict its magnetic behavior and stability.

The Correct Answer and Explanation is:

Molecular Orbital Configuration of Be₂

Beryllium (Be) has an atomic number of 4, and its electron configuration is ( 1s^2 2s^2 ). When two beryllium atoms combine to form the diatomic molecule Be₂, the molecular orbital theory is used to determine the molecular orbital configuration.

The molecular orbitals for Be₂ can be represented as follows:

  1. Bonding Molecular Orbitals:
  • ( \sigma_{1s} ): Filled with 2 electrons from the 1s orbitals of each Be atom.
  • ( \sigma_{2s} ): Filled with 2 electrons from the 2s orbitals of each Be atom.
  1. Antibonding Molecular Orbitals:
  • ( \sigma^*_{2s} ): Unoccupied (0 electrons).

Thus, the molecular orbital configuration for Be₂ is:

[
\text{Be}2: ( \sigma{1s} )^2 ( \sigma_{2s} )^2 ( \sigma^*_{2s} )^0
]

Bond Order Calculation

The bond order can be calculated using the formula:

[
\text{Bond Order} = \frac{(\text{Number of electrons in bonding MOs}) – (\text{Number of electrons in antibonding MOs})}{2}
]

For Be₂:

  • Electrons in bonding MOs: ( 2 (\sigma_{1s}) + 2 (\sigma_{2s}) = 4 )
  • Electrons in antibonding MOs: ( 0 (\sigma^*_{2s}) = 0 )

Therefore, the bond order is:

[
\text{Bond Order} = \frac{4 – 0}{2} = 2
]

Magnetic Behavior and Stability

  1. Magnetic Behavior: Be₂ has no unpaired electrons in its molecular orbitals, making it diamagnetic. This means that it will not be attracted to a magnetic field.
  2. Stability: The bond order of 2 indicates that Be₂ has a strong double bond, suggesting that the molecule is stable. However, due to the relatively small size of beryllium and the resulting weak overlapping of the ( s ) orbitals, Be₂ is not a very stable molecule under normal conditions. In fact, it is considered less stable than other diatomic molecules like O₂ or N₂.

In summary, the molecular orbital configuration of Be₂ reveals a bond order of 2, indicating a stable diatomic molecule that is diamagnetic due to the absence of unpaired electrons.

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