How to find p value from z score on ti 84 plus
The Correct Answer and Explanation is:
To find the p-value from a z-score using the TI-84 Plus calculator, you can follow these steps:
Step-by-Step Guide:
- Turn on the calculator: Press the
ONbutton. - Access the Distribution Menu:
- Press the
2ndbutton, thenVARSto access theDISTRmenu.
- Select the Normalcdf Function:
- For a one-tailed test (if your z-score is positive), scroll down and select
normalcdf(. - If your z-score is negative or you need a two-tailed test, you may use
normalcdffor each side separately.
- Input the Parameters:
- The syntax for
normalcdfis:normalcdf(lower bound, upper bound, mean, standard deviation). - Since you’re working with z-scores (where the mean = 0 and standard deviation = 1), the parameters will be:
- For a right-tailed test: Input
normalcdf(z, 1E99, 0, 1)wherezis your z-score. The1E99represents a very large upper bound. - For a left-tailed test: Input
normalcdf(-1E99, z, 0, 1). - For a two-tailed test: Calculate both tails: for z > 0:
normalcdf(-1E99, -|z|, 0, 1) + normalcdf(z, 1E99, 0, 1).
- For a right-tailed test: Input
- Press Enter: After entering the parameters, press
ENTERto compute the p-value.
Example:
Suppose you have a z-score of 1.96. For a right-tailed test:
- Input:
normalcdf(1.96, 1E99, 0, 1). - The calculator will return a p-value, which in this case is approximately 0.025.
Understanding the p-value:
The p-value represents the probability of obtaining a test statistic at least as extreme as the one observed, assuming the null hypothesis is true. A small p-value (typically ≤ 0.05) indicates strong evidence against the null hypothesis, leading to its rejection. Conversely, a large p-value suggests insufficient evidence to reject the null hypothesis. Thus, the p-value helps determine statistical significance in hypothesis testing, guiding researchers in making informed decisions based on their data.