How do you find the sine, cosine, and tangent values on the unit circle

How do you find the sine, cosine, and tangent values on the unit circle? Provide an example.

The Correct Answer and Explanation is:

To find the sine, cosine, and tangent values on the unit circle, we start by understanding the definition of the unit circle. The unit circle is a circle with a radius of 1 centered at the origin (0,0) in the Cartesian coordinate system. Each point on the unit circle can be described by its coordinates (x, y), where ( x ) represents the cosine of the angle ( \theta ) and ( y ) represents the sine of ( \theta ). This is based on the fundamental trigonometric relationships defined in a right triangle.

  1. Sine (sin): The sine of an angle is defined as the y-coordinate of the point on the unit circle corresponding to that angle. Thus, ( \sin(\theta) = y ).
  2. Cosine (cos): The cosine of an angle is defined as the x-coordinate of the point on the unit circle corresponding to that angle. Thus, ( \cos(\theta) = x ).
  3. Tangent (tan): The tangent of an angle is the ratio of the sine to the cosine. Hence, ( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} = \frac{y}{x} ), provided that ( \cos(\theta) \neq 0 ).

Example:

Let’s consider the angle ( 45^\circ ) (or ( \frac{\pi}{4} ) radians).

  1. Locate the point: On the unit circle, the angle ( 45^\circ ) corresponds to the point ((\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})).
  2. Calculate sine and cosine:
  • Sine: ( \sin(45^\circ) = \frac{\sqrt{2}}{2} )
  • Cosine: ( \cos(45^\circ) = \frac{\sqrt{2}}{2} )
  1. Calculate tangent:
  • Tangent: ( \tan(45^\circ) = \frac{\sin(45^\circ)}{\cos(45^\circ)} = \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1 )

Summary:

Thus, for the angle ( 45^\circ ), we have:

  • ( \sin(45^\circ) = \frac{\sqrt{2}}{2} )
  • ( \cos(45^\circ) = \frac{\sqrt{2}}{2} )
  • ( \tan(45^\circ) = 1 )

These relationships help visualize and calculate trigonometric values efficiently using the unit circle, which is fundamental in trigonometry.

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