What is the mass of Silver in 3.45g AgS?
The Correct Answer and Explanation is :
To calculate the mass of silver (Ag) in 3.45 grams of silver sulfide (AgS), follow these steps:
Step 1: Write the chemical formula and find molar masses
The formula for silver sulfide is AgS, meaning it contains one atom of silver (Ag) and one atom of sulfur (S).
- Molar mass of Ag = 107.87 g/mol
- Molar mass of S = 32.07 g/mol
- Molar mass of AgS = 107.87 g/mol (Ag) + 32.07 g/mol (S) = 139.94 g/mol
Step 2: Determine the proportion of silver in AgS
In one mole of AgS, there is 1 mole of silver. The molar mass of silver is 107.87 g, while the molar mass of AgS is 139.94 g. Thus, the mass fraction of silver in AgS can be calculated as:
[
\text{Fraction of Ag} = \frac{\text{Molar mass of Ag}}{\text{Molar mass of AgS}} = \frac{107.87 \, \text{g/mol}}{139.94 \, \text{g/mol}} \approx 0.770
]
Step 3: Calculate the mass of silver in 3.45g of AgS
To find the mass of silver in 3.45 grams of AgS, multiply the mass of AgS by the fraction of silver in AgS:
[
\text{Mass of Ag} = \text{Mass of AgS} \times \text{Fraction of Ag}
]
[
\text{Mass of Ag} = 3.45 \, \text{g} \times 0.770 \approx 2.66 \, \text{g}
]
Final Answer:
The mass of silver (Ag) in 3.45 grams of silver sulfide (AgS) is approximately 2.66 grams.
Explanation:
This calculation is based on the principle that the mass of a compound can be broken down into the sum of the masses of its elements. By knowing the molar masses of the elements involved and the total mass of the compound, you can determine the mass of any individual component. In this case, knowing that silver makes up approximately 77% of the mass of AgS allows us to find how much of the given 3.45 grams is due to silver. This method is common in stoichiometry and mass balance calculations in chemistry.