What is the molar mass of AlBr3
The Correct Answer and Explanation is :
The molar mass of aluminum bromide (AlBr₃) is calculated by adding the molar masses of its constituent elements, aluminum (Al) and bromine (Br).
Step-by-step Calculation:
- Molar Mass of Aluminum (Al):
- The atomic mass of aluminum (Al) is approximately 26.98 g/mol.
- Molar Mass of Bromine (Br):
- The atomic mass of bromine (Br) is approximately 79.90 g/mol.
- Since there are three bromine atoms in AlBr₃, the total mass contributed by bromine will be:
[
3 \times 79.90 \, \text{g/mol} = 239.70 \, \text{g/mol}
]
- Total Molar Mass of AlBr₃:
To find the total molar mass of AlBr₃, add the molar mass of aluminum to the total molar mass of the bromine atoms:
[
26.98 \, \text{g/mol} + 239.70 \, \text{g/mol} = 266.68 \, \text{g/mol}
]
Thus, the molar mass of AlBr₃ is 266.68 g/mol.
Explanation:
The molar mass is the mass of one mole of a substance, which is equivalent to the molecular weight expressed in grams. The molecular weight corresponds to the sum of the atomic masses of all the atoms in a molecule. In the case of AlBr₃, it consists of one aluminum atom and three bromine atoms. The atomic mass of each element can be found on the periodic table, and multiplying the atomic mass of bromine by three reflects the fact that there are three bromine atoms in each AlBr₃ unit. By summing these values, we determine the total molar mass. This value is crucial in stoichiometric calculations for reactions involving AlBr₃, such as determining the amount of AlBr₃ required or produced in chemical reactions.