A five-ounce glass of wine contains the same amount of alcohol as:
Answers
One pint of whiskey.
One 12-ounce can of beer.
A gallon of wine.
A six-pack of beer.
The Correct Answer and Explanation is :
The correct answer is One 12-ounce can of beer.
Here’s why:
Alcohol content in beverages is often measured in terms of “standard drinks,” which contain about 0.6 ounces (14 grams) of pure alcohol. The alcohol by volume (ABV) percentage varies across different drinks, but the standard drink concept helps compare different beverages in terms of their alcohol content.
Let’s break down the alcohol content of the options provided:
1. Five-ounce glass of wine
- A typical glass of wine is 5 ounces, and most wines have an ABV of around 12-14%.
- For a 12% ABV wine, a 5-ounce glass would contain approximately 0.6 ounces of alcohol (5 oz × 12% = 0.6 oz). This is considered one standard drink.
2. One pint of whiskey
- A pint is 16 ounces, and whiskey typically has a higher ABV, around 40%.
- A pint of whiskey (16 oz) at 40% ABV would contain 6.4 ounces of alcohol (16 oz × 40% = 6.4 oz). This is much more than the alcohol in a 5-ounce glass of wine, so this is not a correct answer.
3. One gallon of wine
- One gallon equals 128 ounces. If we assume a wine ABV of 12%, a gallon of wine would contain 15.36 ounces of alcohol (128 oz × 12% = 15.36 oz). This is far more than the alcohol in a 5-ounce glass of wine.
4. A six-pack of beer
- A six-pack of beer contains six 12-ounce cans. Most beers have around 5% ABV, so each can of beer contains approximately 0.6 ounces of alcohol (12 oz × 5% = 0.6 oz).
- A six-pack would therefore contain 3.6 ounces of alcohol (6 × 0.6 oz), which is more than the alcohol in a 5-ounce glass of wine, so this is also not a correct answer.
Conclusion:
A 5-ounce glass of wine contains roughly the same amount of alcohol as one 12-ounce can of beer. Both have approximately 0.6 ounces of alcohol, making them equivalent in terms of their alcohol content.