Draw the Haworth projection of beta-D-sorbose Fischer projection below

Draw the Haworth projection of beta-D-sorbose Fischer projection below. n pr CH,0H ?? ?? ?? CH20H Show your work Sorbose is a ketose aldose puranose furanose disaccharide oligosaccharide polysaccharide Cellulose is a homopolysaccharide of what monomer units? 1 pt

The correct answer and explanation is:

Haworth Projection of β-D-Sorbose from its Fischer Projection

To draw the Haworth projection of β-D-sorbose from its Fischer projection, we follow these steps:


Step 1: Analyze D-sorbose structure

D-sorbose is a ketose sugar (a monosaccharide with a ketone group) with six carbons. Its Fischer projection includes:

  • Carbon 1: Part of the ketone group.
  • Carbon 2: Has the configuration defining the D-series.
  • Carbons 3–5: Hydroxyl (-OH) and hydrogen (-H) groups attached, determining chirality.
  • Carbon 6: Terminal CH2_2OH group.

Step 2: Cyclization

  • D-sorbose typically forms a furanose (5-membered ring) structure due to the reaction of the hydroxyl group on Carbon 5 with the ketone group on Carbon 2.
  • This cyclization creates a new stereocenter at Carbon 2, forming two anomers: α and β. The β-anomer has the anomeric -OH group on the same side as the CH2_2OH group in the Haworth projection.

Step 3: Draw the Haworth projection

  1. Orient the ring with the oxygen at the top right.
  2. Place the CH2_2OH group above the ring at Carbon 5.
  3. Place the -OH group on Carbon 2 above the plane (β-form).
  4. Assign positions for the -OH groups on Carbons 3 and 4 based on the Fischer projection:
    • -OH on Carbon 3 is below the plane.
    • -OH on Carbon 4 is above the plane.
  5. Add the CH2_2OH group at Carbon 1 below the plane.

Sorbose Classification

  • Ketose: Contains a ketone group.
  • Furanose: Forms a 5-membered ring.
  • Monosaccharide: Simplest sugar unit.

Cellulose Structure

Cellulose is a homopolysaccharide consisting of β-D-glucose units. These units are linked by β(1→4) glycosidic bonds. It forms linear chains that aggregate into microfibrils, giving structural integrity to plant cell walls.

Explanation of β-D-glucose in Cellulose:

  1. Each glucose unit alternates orientation (180° rotation) to allow hydrogen bonding between adjacent chains.
  2. This arrangement makes cellulose strong, insoluble, and ideal for structural purposes.
  3. Humans lack the enzyme cellulase to break β(1→4) linkages, making cellulose indigestible.

Let me know if you’d like me to draw the Haworth projection or elaborate further!

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