Challenge Question Python Codio
We will pass you 2 inputs
an list of numbers
a number, N, to look for
Your job is to loop through the list and find the number specified in the second input. Output the list element index where you find the number.
If N is not found in the list, output -1.
Tip: Remember the break statement? It exits the loop. You can (but don’t have to) use this.
# Get our input from the command line
import sys
N= int(sys.argv[2])
# Convert the list of strings into integers
numbers= []
for i in sys.argv[1].split(“,”):
if(i.isdigit()):
numbers.append(int(i))
# numbers now contains the list of integers
# Write your code below
The Correct Answer and Explanation is :
Below is the solution for the challenge question, along with a detailed explanation.
Solution Code
# Get our input from the command line
import sys
# Parse inputs
N = int(sys.argv[2])
# Convert the list of strings into integers
numbers = []
for i in sys.argv[1].split(","):
if i.isdigit():
numbers.append(int(i))
# Initialize index as -1 to indicate "not found" by default
index = -1
# Loop through the list
for i in range(len(numbers)):
if numbers[i] == N:
index = i # Update index if the number is found
break # Exit the loop once we find the number
# Output the result
print(index)
Explanation (300 Words)
- Input Parsing:
- The program receives two inputs:
- A comma-separated list of numbers (
sys.argv[1]). - A single number,
N(sys.argv[2]), which needs to be found.
- A comma-separated list of numbers (
sys.argv[1]is split into individual elements using.split(","), and each element is checked withisdigit()to confirm it’s a valid integer. Valid integers are added to thenumberslist.
- Search Logic:
- A
forloop iterates over the indices of thenumberslist usingrange(len(numbers)). - Inside the loop, each element is compared with
N. - If a match is found, the index (
i) is assigned to the variableindex, and the loop exits using thebreakstatement.
- Default Value for Index:
- Before the loop,
indexis initialized to-1to represent “not found.” - If the loop completes without finding
N, the value remains-1.
- Efficiency:
- The
breakstatement optimizes performance by stopping the loop onceNis found, avoiding unnecessary iterations.
- Output:
- The program prints the index where
Nis found, or-1if it isn’t found.
- Edge Cases:
- If
sys.argv[1]is empty, the output is-1. - If
Nappears multiple times, only the first occurrence is returned. - Non-integer inputs in the list are ignored, ensuring robustness.
This approach balances clarity and efficiency, ensuring the code works well for varied inputs.