Solute Mass of solute Moles of solute Volume of solution Molarity of solution MgSO4 0.598 g _ 20.0 mL NaOH 110.0 mL 1.75 M CH3OH 12.0 g _ 0.550 M A)

Complete the table: Solute Mass of solute Moles of solute Volume of solution Molarity of solution MgSO4 0.598 g _____ 20.0 mL _____ NaOH _____ _____ 110.0 mL 1.75 M CH3OH 12.0 g _____ _____ 0.550 M A) Complete the row for MgSO4 B) Complete the row for NaOH C) Complete the row for CH3OH

Complete the table:

Solute	Mass of solute	Moles of solute	Volume of solution	Molarity of solution
MgSO4	0.598 g	_____	20.0 mL	_____
NaOH	_____	_____	110.0 mL	1.75 M
CH3OH	12.0 g	_____	_____	0.550 M

A) Complete the row for MgSO₄

B) Complete the row for NaOH

C) Complete the row for CH₃OH

The Correct Answer and Explanation is :

To complete the table, we need to calculate the missing values for each solute using the relationships between mass, moles, volume, and molarity.

A) MgSO₄

Given:

• Mass of solute: 0.598 g
• Volume of solution: 20.0 mL (0.0200 L)

1. Moles of MgSO₄:

• Molar mass of MgSO₄ = 120.37 g/mol
• Moles = Mass / Molar mass
• Moles = 0.598 g / 120.37 g/mol ≈ 0.00497 mol

1. Molarity of solution:

• Molarity (M) = Moles / Volume (L)
• Molarity = 0.00497 mol / 0.0200 L ≈ 0.2485 M

B) NaOH

Given:

• Molarity of solution: 1.75 M
• Volume of solution: 110.0 mL (0.1100 L)

1. Moles of NaOH:

• Moles = Molarity × Volume (L)
• Moles = 1.75 M × 0.1100 L = 0.1925 mol

1. Mass of NaOH:

• Molar mass of NaOH = 40.00 g/mol
• Mass = Moles × Molar mass
• Mass = 0.1925 mol × 40.00 g/mol = 7.70 g

C) CH₃OH

Given:

• Mass of solute: 12.0 g
• Molarity of solution: 0.550 M

1. Moles of CH₃OH:

• Molar mass of CH₃OH = 32.04 g/mol
• Moles = Mass / Molar mass
• Moles = 12.0 g / 32.04 g/mol ≈ 0.3745 mol

1. Volume of solution:

• Volume (L) = Moles / Molarity
• Volume = 0.3745 mol / 0.550 M ≈ 0.6809 L
• Volume = 0.6809 L × 1000 mL/L ≈ 681 mL

Summary Table:

Solute	Mass of solute	Moles of solute	Volume of solution	Molarity of solution
MgSO₄	0.598 g	0.00497 mol	20.0 mL (0.0200 L)	0.2485 M
NaOH	7.70 g	0.1925 mol	110.0 mL (0.1100 L)	1.75 M
CH₃OH	12.0 g	0.3745 mol	681 mL (0.681 L)	0.550 M

Explanation:

1. Moles of Solute:

• Calculated by dividing the mass of the solute by its molar mass.

1. Molarity of Solution:

• Determined by dividing the moles of solute by the volume of the solution in liters.

1. Volume of Solution:

• Found by dividing the moles of solute by the molarity of the solution.

These calculations are essential for understanding solution concentrations and preparing solutions with desired molarities.