1.15 grams of KNO3
How many moles of KNO3?
How many moles of K+? explain briefly
How many moles of NO3-? Explain briefly
2.What are the end products of glycolysis? Select all that apply. Explain briefly
The Correct Answer and Explanation is :
1. Moles of KNO3
To find the number of moles of KNO3, you need to use the formula:
[
\text{moles} = \frac{\text{mass}}{\text{molar mass}}
]
The molar mass of KNO3 is calculated by adding the atomic masses of each element:
- Potassium (K) = 39.1 g/mol
- Nitrogen (N) = 14.0 g/mol
- Oxygen (O) = 16.0 g/mol (3 atoms of oxygen, so 3 * 16.0 = 48.0 g/mol)
Molar mass of KNO3 = 39.1 + 14.0 + 48.0 = 101.1 g/mol
Now, calculate the moles of KNO3:
[
\text{moles of KNO3} = \frac{1.15 \, \text{g}}{101.1 \, \text{g/mol}} = 0.0114 \, \text{mol}
]
2. Moles of K+ and NO3-
Since KNO3 dissociates into K+ and NO3- in a 1:1 ratio, the moles of K+ and NO3- will be the same as the moles of KNO3.
- Moles of K+ = 0.0114 mol
- Moles of NO3- = 0.0114 mol
Explanation:
- Potassium nitrate (KNO3) dissociates in water to form one potassium ion (K+) and one nitrate ion (NO3-) for every formula unit of KNO3. So, if you have 0.0114 mol of KNO3, you will have 0.0114 mol of K+ and 0.0114 mol of NO3-.
3. End Products of Glycolysis
The end products of glycolysis are:
- 2 Pyruvate molecules
- 2 ATP molecules (net gain)
- 2 NADH molecules
- 2 H2O molecules
- 2 H+ ions
Explanation:
Glycolysis is the first step in cellular respiration and occurs in the cytoplasm. It is an anaerobic process (does not require oxygen) that breaks down one molecule of glucose (C6H12O6) into two molecules of pyruvate. The pathway is divided into two phases:
- Energy Investment Phase: This phase consumes 2 ATP molecules to phosphorylate glucose, making it more reactive. The glucose molecule is then split into two three-carbon molecules, each of which will continue in the second phase.
- Energy Payoff Phase: In this phase, the energy stored in the three-carbon molecules is harvested to produce ATP and NADH. For each three-carbon molecule, 2 ATP and 1 NADH are produced, resulting in a total of 4 ATP and 2 NADH from the two three-carbon molecules. Since 2 ATP were consumed in the earlier phase, the net gain is 2 ATP.
Additionally, 2 molecules of water (H2O) are produced as a byproduct of the reactions in glycolysis. NAD+ is reduced to NADH, which can later be used in the electron transport chain if oxygen is available.
In summary, the end products of glycolysis are 2 pyruvate molecules, 2 ATP (net), 2 NADH, and 2 H2O.