Which weighs more, 5.00 g or 0.0225 mol of acetaminophen 1C8H9NO 22?
The Correct Answer and Explanation is :
To determine which weighs more between 5.00 grams and 0.0225 moles of acetaminophen (C₈H₉NO₂), we first need to calculate the mass of 0.0225 moles of acetaminophen. To do this, we need to know the molar mass of acetaminophen.
Step 1: Calculate the Molar Mass of Acetaminophen
The molecular formula of acetaminophen is C₈H₉NO₂. To find the molar mass, we sum up the atomic masses of each element in the molecule:
- Carbon (C) has an atomic mass of approximately 12.01 g/mol.
- Hydrogen (H) has an atomic mass of approximately 1.008 g/mol.
- Nitrogen (N) has an atomic mass of approximately 14.01 g/mol.
- Oxygen (O) has an atomic mass of approximately 16.00 g/mol.
So, the molar mass of acetaminophen is:
[
(8 \times 12.01) + (9 \times 1.008) + (1 \times 14.01) + (2 \times 16.00)
]
[
= 96.08 + 9.072 + 14.01 + 32.00 = 151.16 \, \text{g/mol}
]
Step 2: Calculate the Mass of 0.0225 Moles of Acetaminophen
Now, to find the mass of 0.0225 moles of acetaminophen, we use the formula:
[
\text{Mass} = \text{Moles} \times \text{Molar Mass}
]
Substituting the values:
[
\text{Mass} = 0.0225 \, \text{mol} \times 151.16 \, \text{g/mol} = 3.4 \, \text{g}
]
Step 3: Compare the Two Quantities
We are comparing:
- 5.00 g
- 3.4 g (the mass of 0.0225 moles of acetaminophen)
Clearly, 5.00 g weighs more than 3.4 g.
Conclusion
Therefore, 5.00 g weighs more than 0.0225 moles of acetaminophen.