Gas Pressures Can Be Expressed In Units Of MmHg, Atm, Torr, And KPa. Convert These Pressure Values.
A 730. MmHg To Atm Pressure Atm
B 1.85 Atm To MmHg Pressure = MmHg
C 548 MmHg To Torr Pressure = Torr
D 730. MmHg To KPa Pressure = KPa
E 800. KPa To Atm Pressure = Atm
The Correct Answer and Explanation is :
To convert gas pressures between different units, we need to use the following conversion factors:
- 1 atm = 760 mmHg = 760 Torr
- 1 atm = 101.325 kPa
- 1 Torr = 1 mmHg
A) 730 mmHg to atm
To convert from mmHg to atm, we use the conversion factor:
[ 1 \, \text{atm} = 760 \, \text{mmHg} ]
Thus:
[
\text{Pressure (atm)} = \frac{730 \, \text{mmHg}}{760 \, \text{mmHg/atm}} \approx 0.9605 \, \text{atm}
]
B) 1.85 atm to mmHg
To convert from atm to mmHg, we use the conversion factor:
[ 1 \, \text{atm} = 760 \, \text{mmHg} ]
Thus:
[
\text{Pressure (mmHg)} = 1.85 \, \text{atm} \times 760 \, \text{mmHg/atm} = 1406 \, \text{mmHg}
]
C) 548 mmHg to Torr
Since 1 mmHg is equivalent to 1 Torr, we can directly say:
[
\text{Pressure (Torr)} = 548 \, \text{mmHg} = 548 \, \text{Torr}
]
D) 730 mmHg to kPa
To convert from mmHg to kPa, we first convert mmHg to atm and then atm to kPa:
[
1 \, \text{atm} = 101.325 \, \text{kPa}, \quad 1 \, \text{atm} = 760 \, \text{mmHg}
]
Thus:
[
\text{Pressure (kPa)} = \frac{730 \, \text{mmHg}}{760 \, \text{mmHg/atm}} \times 101.325 \, \text{kPa/atm} \approx 98.4 \, \text{kPa}
]
E) 800 kPa to atm
To convert from kPa to atm:
[
1 \, \text{atm} = 101.325 \, \text{kPa}
]
Thus:
[
\text{Pressure (atm)} = \frac{800 \, \text{kPa}}{101.325 \, \text{kPa/atm}} \approx 7.90 \, \text{atm}
]
Summary of Results:
- 730 mmHg = 0.9605 atm
- 1.85 atm = 1406 mmHg
- 548 mmHg = 548 Torr
- 730 mmHg = 98.4 kPa
- 800 kPa = 7.90 atm
Understanding pressure unit conversions is important for comparing measurements across different systems. By knowing the relationships between different units like mmHg, atm, Torr, and kPa, we can easily convert one value to another for consistent analysis, especially in fields like chemistry and physics where pressure plays a crucial role in various calculations.