The Chemical Formula For Barium Sulfide Is Bas. A Chemist Determined By Measurements That 0.085 Moles Of Barium Sulfide Participate In A Chemical Reaction. Calculate The Mass Of Barium Sulfide That Participates Be Sure Your Answer Has The Correct Number Of Significant Digits. D. ?
The Correct Answer and Explanation is :
To calculate the mass of barium sulfide (BaS) that participates in the chemical reaction, we can follow these steps:
Step 1: Understanding the problem
The chemist measured that 0.085 moles of barium sulfide participate in the reaction. The chemical formula of barium sulfide is BaS, meaning one molecule consists of one atom of barium (Ba) and one atom of sulfur (S).
Step 2: Finding the molar mass of barium sulfide (BaS)
To calculate the mass of a substance, we first need to know its molar mass. The molar mass of BaS is the sum of the molar masses of barium (Ba) and sulfur (S):
- The molar mass of barium (Ba) is approximately 137.33 g/mol.
- The molar mass of sulfur (S) is approximately 32.07 g/mol.
So, the molar mass of BaS is:
[
\text{Molar mass of BaS} = 137.33 \, \text{g/mol} + 32.07 \, \text{g/mol} = 169.40 \, \text{g/mol}
]
Step 3: Using the molar mass to find the mass of barium sulfide
The formula to calculate the mass of a substance from its moles is:
[
\text{Mass} = \text{Moles} \times \text{Molar mass}
]
In this case, we have 0.085 moles of BaS. Using the molar mass we just calculated (169.40 g/mol):
[
\text{Mass of BaS} = 0.085 \, \text{mol} \times 169.40 \, \text{g/mol} = 14.396 \, \text{g}
]
Step 4: Significant figures
The number 0.085 moles has 2 significant figures. According to the rules of significant figures, the result should be rounded to 2 significant figures. So, the mass of BaS will be rounded to:
[
\boxed{14.40 \, \text{g}}
]
Conclusion:
The mass of barium sulfide (BaS) that participates in the chemical reaction is 14.40 grams. This is the result after rounding to the correct number of significant digits based on the given data.
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