Tetrahydrofuran has a density of 0.886 g/mL

Tetrahydrofuran has a density of 0.886 g/mL. Calculate the mass of 41.6 mL of Tetrahydrofuran. Give your answer to the correct number of significant figures

The Correct Answer and Explanation is :

To calculate the mass of a given volume of Tetrahydrofuran (THF), we can use the formula:

[
\text{Mass} = \text{Density} \times \text{Volume}
]

Step-by-step Calculation:

  1. Given data:
  • Density of Tetrahydrofuran (THF) = 0.886 g/mL
  • Volume = 41.6 mL
  1. Apply the formula:
    [
    \text{Mass} = 0.886 \, \text{g/mL} \times 41.6 \, \text{mL}
    ]
  2. Calculation:
    [
    \text{Mass} = 36.886 \, \text{g}
    ]
  3. Significant Figures:
  • The volume, 41.6 mL, has 3 significant figures.
  • The density, 0.886 g/mL, has 3 significant figures.
  • Since the result is a multiplication, we should round the final result to 3 significant figures.

So, the mass of 41.6 mL of Tetrahydrofuran is:

[
\boxed{36.9 \, \text{g}}
]

Explanation:

When performing calculations involving measured quantities, it’s crucial to adhere to the rules of significant figures. In this case, both the volume and density were given with 3 significant figures. When multiplying or dividing, the result should be rounded to the same number of significant figures as the least precise measurement. This ensures that the final answer reflects the precision of the input data.

Here, we used the formula for mass by multiplying the density by the volume. We rounded the result to 3 significant figures, which is appropriate given that the input data had that level of precision. Therefore, the final mass of 41.6 mL of Tetrahydrofuran is 36.9 grams.

Now, let me generate an image to illustrate this process.

Here is an illustration that shows the process of calculating the mass of Tetrahydrofuran using the formula ( \text{Mass} = \text{Density} \times \text{Volume} ). It visualizes how the density and volume relate to the mass calculation. Let me know if you’d like any further details or clarification!

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