How many moles are 1.20 x 10^25 atoms of phosphorus? 2. How many atoms are in 0.750 moles of zinc? 3. How many molecules are in 0.400 moles or N2O5? 1. How many moles are 1.20 x 10^25 atoms of phosphorus? 2. How many atoms are in 0.750 moles of zinc? 3. How many molecules are in 0.400 moles or N2O5?
The Correct Answer and Explanation is :
Let’s address each question one by one, including the necessary calculations and explanations:
1. How many moles are in 1.20 x 10^25 atoms of phosphorus?
To calculate the number of moles from the number of atoms, we use Avogadro’s number, which is approximately (6.022 \times 10^{23}) atoms per mole. The formula for this calculation is:
[
\text{moles} = \frac{\text{atoms}}{6.022 \times 10^{23}}
]
For phosphorus:
[
\text{moles of phosphorus} = \frac{1.20 \times 10^{25}}{6.022 \times 10^{23}} \approx 19.94 \, \text{moles}
]
So, there are approximately 19.94 moles of phosphorus in (1.20 \times 10^{25}) atoms.
2. How many atoms are in 0.750 moles of zinc?
To find the number of atoms in a given number of moles, we again use Avogadro’s number:
[
\text{atoms} = \text{moles} \times 6.022 \times 10^{23}
]
For zinc:
[
\text{atoms of zinc} = 0.750 \times 6.022 \times 10^{23} \approx 4.517 \times 10^{23} \, \text{atoms}
]
So, there are approximately (4.52 \times 10^{23}) atoms in 0.750 moles of zinc.
3. How many molecules are in 0.400 moles of (N_2O_5)?
To find the number of molecules in a given number of moles of a compound, we use the same approach as with atoms:
[
\text{molecules} = \text{moles} \times 6.022 \times 10^{23}
]
For (N_2O_5):
[
\text{molecules of } N_2O_5 = 0.400 \times 6.022 \times 10^{23} \approx 2.409 \times 10^{23} \, \text{molecules}
]
So, there are approximately (2.41 \times 10^{23}) molecules in 0.400 moles of (N_2O_5).
Summary of Results:
- 19.94 moles of phosphorus in (1.20 \times 10^{25}) atoms.
- (4.52 \times 10^{23}) atoms in 0.750 moles of zinc.
- (2.41 \times 10^{23}) molecules in 0.400 moles of (N_2O_5).
Let me know if you need any further clarification or if you’d like me to generate a diagram for these calculations!