Write a balanced ionic equation for this acid-base reaction: 2CsOH(aq)+H2SO4(aq)→ write net ionic equation for this acid-base reaction: 2CsOH(aq)+H2SO4(aq)→  Write a balanced ionic equation for this acid-base reaction: Ca(OH)2(aq)+2CH3CO2H(aq)→ Write net ionic equation for this acid-base reaction: Ca(OH)2(aq)+2CH3CO2H(aq)→
Write a balanced ionic equation for this acid-base reaction: 2CsOH(aq)+H2SO4(aq)→
write net ionic equation for this acid-base reaction: 2CsOH(aq)+H2SO4(aq)→ÂÂ
 Write a balanced ionic equation for this acid-base reaction: Ca(OH)2(aq)+2CH3CO2H(aq)→
Write net ionic equation for this acid-base reaction: Ca(OH)2(aq)+2CH3CO2H(aq)→
The Correct Answer and Explanation is :
Let’s address the two acid-base reactions you mentioned by writing the balanced ionic equations and their corresponding net ionic equations.
1. Reaction between Cesium Hydroxide (CsOH) and Sulfuric Acid (H₂SO₄)
The balanced molecular equation is:
[
2CsOH(aq) + H_2SO_4(aq) \rightarrow Cs_2SO_4(aq) + 2H_2O(l)
]
Step 1: Write the ionic equation:
Since CsOH is a strong base and H₂SO₄ is a strong acid, they dissociate completely in aqueous solution:
[
2Cs^+(aq) + 2OH^-(aq) + 2H^+(aq) + SO_4^{2-}(aq) \rightarrow Cs_2SO_4(aq) + 2H_2O(l)
]
Step 2: Write the net ionic equation:
In this case, Cs⁺ and SO₄²⁻ are spectator ions and do not participate in the actual acid-base reaction. Therefore, the net ionic equation is:
[
2OH^-(aq) + 2H^+(aq) \rightarrow 2H_2O(l)
]
2. Reaction between Calcium Hydroxide (Ca(OH)₂) and Acetic Acid (CH₃COOH)
The balanced molecular equation is:
[
Ca(OH)_2(aq) + 2CH_3COOH(aq) \rightarrow Ca(CH_3COO)_2(aq) + 2H_2O(l)
]
Step 1: Write the ionic equation:
Ca(OH)₂ dissociates into Ca²⁺ and OH⁻ ions, while acetic acid (CH₃COOH) is a weak acid and does not fully dissociate, but we consider the ions involved in the neutralization:
[
Ca^{2+}(aq) + 2OH^-(aq) + 2CH_3COOH(aq) \rightarrow Ca(CH_3COO)_2(aq) + 2H_2O(l)
]
Step 2: Write the net ionic equation:
The acetic acid molecules do not dissociate completely, so no spectator ions are involved here, and the net ionic equation is:
[
Ca^{2+}(aq) + 2OH^-(aq) + 2H^+(aq) + 2CH_3COO^-(aq) \rightarrow Ca(CH_3COO)_2(aq) + 2H_2O(l)
]
However, since acetic acid doesn’t fully dissociate in the solution, the net ionic equation will involve neutralizing the OH⁻ with H⁺:
[
2OH^-(aq) + 2H^+(aq) \rightarrow 2H_2O(l)
]
Explanation:
In these acid-base reactions, the general mechanism involves an exchange between hydroxide ions (OH⁻) from the base (CsOH or Ca(OH)₂) and hydrogen ions (H⁺) from the acid (H₂SO₄ or CH₃COOH). The hydroxide ions neutralize the hydrogen ions to form water (H₂O), and the products of the reactions include a salt (Cesium sulfate, Cs₂SO₄, or calcium acetate, Ca(CH₃COO)₂) and water.
These reactions follow the typical behavior of strong acids and strong bases (like H₂SO₄ and CsOH), which dissociate completely in aqueous solution. On the other hand, the reaction with acetic acid (CH₃COOH), a weak acid, involves a less complete dissociation but still results in the neutralization of hydroxide ions to form water.
Let me generate an image to visually represent the net ionic equations.
Here is the scientific illustration showing the two acid-base reactions with their dissociation processes and products. It should help visualize the neutralization and the ions involved in each reaction. Let me know if you need further clarification!
