Thiophene is common monomer used in may conductiong polymers

Thiophene is common monomer used in may conductiong polymers.
Chemical formula of Thiophene: C4H4S
Provide answers of the following calculations:
Q1: Calculate molar mass of Thiophene.
Q2: Calculate how many moles of Thiophene in 2.10 g Thiophene.
Q3: Calculate how many Thiophene molecules are present in 2.10 g Thiophene.
Avogadro’s number = 6.022 x 1023

The Correct Answer and Explanation is :

Here are the answers to the calculations:

  1. Molar Mass of Thiophene:
    The molar mass of Thiophene (C4H4S) is calculated by adding the atomic masses of the elements involved:
  • Carbon (C) has an atomic mass of 12.01 g/mol, and there are 4 carbon atoms.
  • Hydrogen (H) has an atomic mass of 1.008 g/mol, and there are 4 hydrogen atoms.
  • Sulfur (S) has an atomic mass of 32.07 g/mol, and there is 1 sulfur atom. The molar mass of Thiophene is:
    [
    4(12.01) + 4(1.008) + 1(32.07) = 48.04 + 4.032 + 32.07 = 84.142 \text{ g/mol}
    ]
  1. Moles of Thiophene in 2.10 g:
    Using the formula ( \text{moles} = \frac{\text{mass}}{\text{molar mass}} ), we calculate the moles in 2.10 g of Thiophene:
    [
    \text{moles} = \frac{2.10 \, \text{g}}{84.142 \, \text{g/mol}} = 0.02496 \, \text{mol}
    ]
  2. Number of Thiophene Molecules in 2.10 g:
    To find the number of molecules, we multiply the moles by Avogadro’s number (6.022 x 10^23 molecules/mol):
    [
    \text{molecules} = 0.02496 \, \text{mol} \times 6.022 \times 10^{23} = 1.50 \times 10^{22} \, \text{molecules}
    ]

Thus, the answers are:

  • Molar Mass: 84.142 g/mol
  • Moles: 0.025 mol
  • Molecules: 1.50 x 10²² molecules

I’ll now generate an image that summarizes these calculations.

Here is an educational illustration summarizing the calculations for the molar mass, moles, and molecules of Thiophene (C4H4S). It includes the key steps and the molecular structure of Thiophene. Let me know if you need any further explanations or modifications!

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