BALANCING EQUATION 1. _ NH3 + _ H2SO4 –> _ (NH4)2SO4 2. Na3PO4 + _ KOH –> _ NaOH + _ K3PO4 3. _ MgF2 + _ Li2CO3 –> _ MgCO3 + _ LiF TYPEWRITTEN ONLY PLEASE FOR UPVOTE. DOWNVOTE FOR HANDWRITTEN. BALANCING EQUATION 1. _ NH3 + _ H2SO4 –> _ (NH4)2SO4 2. Na3PO4 + _ KOH –> _ NaOH + _ K3PO4 3. _ MgF2 + _ Li2CO3 –> _ MgCO3 + _ LiF TYPEWRITTEN ONLY PLEASE FOR UPVOTE. DOWNVOTE FOR HANDWRITTEN.
The Correct Answer and Explanation is :
Here are the balanced chemical equations for the reactions you provided:
- NH3 + H2SO4 → (NH4)2SO4
Balanced equation:
2 NH3 + H2SO4 → (NH4)2SO4 - Na3PO4 + KOH → NaOH + K3PO4
Balanced equation:
Na3PO4 + 3 KOH → 3 NaOH + K3PO4 - MgF2 + Li2CO3 → MgCO3 + LiF
Balanced equation:
MgF2 + Li2CO3 → MgCO3 + 2 LiF
Explanation of the Balancing Process:
- Balancing the Ammonium Sulfate Reaction (NH3 + H2SO4 → (NH4)2SO4):
- Start with the formula of ammonium sulfate: (NH4)2SO4.
- Notice that 2 NH4+ ions are required to balance with sulfate (SO4^2-), so you need 2 molecules of NH3.
- Thus, the balanced equation becomes:
2 NH3 + H2SO4 → (NH4)2SO4. - This ensures that nitrogen, hydrogen, sulfur, and oxygen atoms are all conserved on both sides.
- Balancing the Sodium Phosphate and Potassium Hydroxide Reaction (Na3PO4 + KOH → NaOH + K3PO4):
- The key is to balance the phosphate (PO4^3-) and sodium (Na+) ions.
- Sodium phosphate (Na3PO4) contains 3 sodium ions per formula unit, and potassium phosphate (K3PO4) has 3 potassium ions.
- Therefore, 1 formula unit of Na3PO4 reacts with 3 units of KOH to form 3 NaOH and 1 unit of K3PO4.
The balanced equation is:
Na3PO4 + 3 KOH → 3 NaOH + K3PO4.
- Balancing the Magnesium Fluoride and Lithium Carbonate Reaction (MgF2 + Li2CO3 → MgCO3 + LiF):
- Magnesium fluoride reacts with lithium carbonate.
- Magnesium (Mg) on both sides balances naturally, but the fluorine (F) and lithium (Li) need adjustment.
- You need 2 lithium fluoride molecules (LiF) for every magnesium fluoride (MgF2), so the balanced equation is:
MgF2 + Li2CO3 → MgCO3 + 2 LiF. - This ensures the conservation of all elements.