For aluminum, the heat capacity at constant volume Cv at 30 K is 0.81 J/mol-K, and the Debye temperature is 375 K

For aluminum, the heat capacity at constant volume Cv at 30 K is 0.81 J/mol-K, and the Debye temperature is 375 K. Estimate the specific heat
(a) At 50 K and
(b) At 425 K.

The Correct Answer and Explanation is :

To estimate the specific heat of aluminum at 50 K and 425 K, we use the Debye model, which describes the heat capacity of solids at different temperature ranges.

Debye Model Formula for Heat Capacity:

The Debye model gives the heat capacity at constant volume as:

[
C_V = 9Nk_B \left(\frac{T}{\Theta_D}\right)^3 \int_0^{\Theta_D/T} \frac{x^4 e^x}{(e^x -1)^2} dx
]

where:

  • ( C_V ) = heat capacity at constant volume
  • ( N ) = number of atoms per mole (Avogadro’s number)
  • ( k_B ) = Boltzmann constant
  • ( T ) = temperature
  • ( \Theta_D ) = Debye temperature
  • ( x = \frac{h \nu}{k_B T} ), integration variable

However, in practical calculations, we use approximations based on temperature ranges:

  1. For ( T \ll \Theta_D ) (low-temperature regime, ( T < 0.1\Theta_D )):
    [
    C_V \approx \frac{12\pi^4}{5} Nk_B \left(\frac{T}{\Theta_D}\right)^3
    ]
    This follows the Debye (T^3) Law.
  2. For ( T \gg \Theta_D ) (high-temperature regime, ( T > \Theta_D )):
    [
    C_V \approx 3Nk_B
    ]
    This approaches the Dulong–Petit limit (~25 J/mol-K for aluminum).

(a) Specific Heat at 50 K

Since ( 50 K < \Theta_D ), we use the Debye approximation:
[
C_V(50K) = C_V(30K) \times \left(\frac{50}{30}\right)^3
]

[
C_V(50K) = 0.81 \times \left(\frac{50}{30}\right)^3
]

[
C_V(50K) \approx 3.74 J/mol-K
]


(b) Specific Heat at 425 K

Since ( 425 K > \Theta_D ), aluminum is in the classical regime, where the heat capacity approaches the Dulong–Petit law:

[
C_V(425K) \approx 3R = 24.9 J/mol-K
]

where ( R ) is the gas constant (( 8.314 J/mol-K )).


Final Answers:

  • ( C_V(50K) \approx 3.74 J/mol-K )
  • ( C_V(425K) \approx 24.9 J/mol-K ) (approaching the classical limit)

I’ll now generate an image to illustrate this.

Here is the generated diagram illustrating the heat capacity of aluminum as a function of temperature. It shows the two main regions: the low-temperature Debye ( T^3 ) regime and the high-temperature Dulong-Petit limit. Let me know if you need any modifications!

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