After Completing A Lab Experiment Where 2.1 G Of Isoborneol (Molar Mass=154.25 G/Mol) Was Used With 7 ML Of Glacial Acetic Acid (Molar Mass=60.052 G/Mol

After Completing A Lab Experiment Where 2.1 G Of Isoborneol (Molar Mass=154.25 G/Mol) Was Used With 7 ML Of Glacial Acetic Acid (Molar Mass=60.052 G/Mol; Density= 1.05 G/ML), And 18 ML Of Bleach (Nacio). 1.838 G Of Camphor Was Obtained (Molar Mass=152.23 G/Mol). Find The Limiting Reagent

The Correct Answer and Explanation is :

Solution: Finding the Limiting Reagent

Step 1: Convert Given Masses and Volumes to Moles

1. Moles of Isoborneol
[
\text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{2.1 \text{ g}}{154.25 \text{ g/mol}} = 0.01362 \text{ moles}
]

2. Moles of Acetic Acid
First, find the mass of acetic acid:
[
\text{Mass} = \text{Density} \times \text{Volume} = (1.05 \text{ g/mL}) \times (7 \text{ mL}) = 7.35 \text{ g}
]
Now, convert to moles:
[
\text{Moles} = \frac{7.35 \text{ g}}{60.052 \text{ g/mol}} = 0.1224 \text{ moles}
]

3. Moles of Bleach (Sodium Hypochlorite, NaOCl)
Since the concentration of bleach is not given, we assume it to be a standard household bleach solution (~5% NaOCl by weight). Assuming its density is ~1.10 g/mL, and its molar mass is 74.44 g/mol:

[
\text{Mass of bleach} = (1.10 \text{ g/mL}) \times (18 \text{ mL}) = 19.8 \text{ g}
]

Assuming 5% NaOCl:
[
\text{Mass of NaOCl} = 0.05 \times 19.8 = 0.99 \text{ g}
]

[
\text{Moles of NaOCl} = \frac{0.99 \text{ g}}{74.44 \text{ g/mol}} = 0.0133 \text{ moles}
]


Step 2: Identify the Limiting Reagent

The oxidation reaction follows the equation:

[
\text{Isoborneol} + \text{NaOCl} \rightarrow \text{Camphor}
]

From the balanced reaction, the molar ratio of isoborneol to NaOCl is 1:1.

  • Moles of isoborneol = 0.01362 moles
  • Moles of NaOCl = 0.0133 moles

Since NaOCl has fewer moles, NaOCl is the limiting reagent.


Conclusion

The limiting reagent is sodium hypochlorite (NaOCl) since it has fewer moles than isoborneol and is consumed first in the reaction. This means the amount of camphor formed is determined by the moles of NaOCl available.

Now, I will generate an image illustrating this reaction.

I’ve generated an image illustrating the oxidation of isoborneol to camphor, including labeled glassware, chemical quantities, and the final product on a weighing scale. Let me know if you need any modifications or additional details!

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