What product(s) are expected in the ethoxide-promoted ß-elimination reaction of 1-chloro-1-methylcyclohexane

What product(s) are expected in the ethoxide-promoted ß-elimination reaction of 1-chloro-1-methylcyclohexane? Omit ions, salts, and ethanol from your response. Draw the product(s).

The correct answer and explanation is :

Answer:

The expected product of the ethoxide-promoted β-elimination reaction of 1-chloro-1-methylcyclohexane is 1-methylcyclohexene.

Explanation:

The reaction mechanism follows the E2 (bimolecular elimination) mechanism, which occurs under strong base conditions like ethoxide (EtO⁻). Here’s how the reaction proceeds:

  1. Formation of the Transition State:
  • The strong base (EtO⁻) abstracts a β-hydrogen (H) from the carbon adjacent to the carbon bearing the leaving group (Cl).
  • This removal of the proton must occur in an anti-periplanar (coplanar but opposite-facing) geometry to the leaving group for the best orbital alignment, which is characteristic of an E2 mechanism.
  1. Elimination of the Leaving Group:
  • As the β-hydrogen is removed, the electrons from the C-H bond shift to form a π bond between the α- and β-carbons.
  • Simultaneously, the chlorine (Cl⁻) leaves, forming the alkene.
  1. Formation of the Alkene Product:
  • Since 1-chloro-1-methylcyclohexane has only one available β-hydrogen (on the β-carbon adjacent to the chlorine), only one possible alkene product can form: 1-methylcyclohexene.
  • The formation of a double bond follows Zaitsev’s rule, which states that the most substituted and stable alkene is preferentially formed.

Why Only 1-Methylcyclohexene?

  • The β-hydrogen on carbon-2 is eliminated, leading to the formation of 1-methylcyclohexene.
  • No regioisomeric products are formed because the only β-hydrogen available leads directly to the formation of this particular alkene.

Summary:

  • The reaction follows an E2 mechanism because of the strong base (ethoxide).
  • The product is 1-methylcyclohexene as dictated by Zaitsev’s rule.
  • The elimination requires an anti-periplanar conformation, ensuring that elimination proceeds in a single step without intermediates.

Thus, 1-methylcyclohexene is the sole product of this reaction.

Scroll to Top