Enter the formula for each ionic compounds. express your answer as a chemical formula.
Lead(II) chromate
Iron (III) fluoride
Iron(II) phosphate
Potassium hydroxide
The correct answer and explanation is :
Let’s break down the chemical formulas for each of these ionic compounds, keeping in mind the charges of the ions involved.
1. Lead(II) Chromate:
- Formula: PbCrO₄
Explanation:
Lead(II) chromate is made up of lead ions with a +2 charge and chromate ions with a -2 charge. Lead(II) is denoted as Pb²⁺, and chromate is represented by CrO₄²⁻. Since both the lead ion and chromate ion have equal and opposite charges, they combine in a 1:1 ratio to form PbCrO₄.
2. Iron (III) Fluoride:
- Formula: FeF₃
Explanation:
Iron (III) fluoride is composed of iron(III) ions and fluoride ions. The iron(III) ion has a +3 charge (Fe³⁺), and the fluoride ion has a -1 charge (F⁻). To balance the charges, three fluoride ions are needed for every iron(III) ion. Therefore, the formula for iron (III) fluoride is FeF₃.
3. Iron (II) Phosphate:
- Formula: Fe₃(PO₄)₂
Explanation:
Iron(II) phosphate consists of iron(II) ions and phosphate ions. The iron(II) ion has a +2 charge (Fe²⁺), and the phosphate ion has a -3 charge (PO₄³⁻). To balance the charges, three iron(II) ions are needed to combine with two phosphate ions, resulting in the formula Fe₃(PO₄)₂.
4. Potassium Hydroxide:
- Formula: KOH
Explanation:
Potassium hydroxide is made up of potassium ions (K⁺) and hydroxide ions (OH⁻). The potassium ion has a +1 charge, and the hydroxide ion has a -1 charge. Since the charges of the two ions are equal in magnitude but opposite in sign, they combine in a 1:1 ratio to form the formula KOH.
Summary:
- Lead(II) Chromate: PbCrO₄
- Iron(III) Fluoride: FeF₃
- Iron(II) Phosphate: Fe₃(PO₄)₂
- Potassium Hydroxide: KOH
Each formula is determined by balancing the positive and negative charges of the ions involved, ensuring that the compound is electrically neutral.