A sleep time of 15.9 hours per day for a newborn baby is at the percentile of the distribution of sleep times for all newborn babies

A sleep time of 15.9 hours per day for a newborn baby is at the percentile of the distribution of sleep times for all newborn babies. Assuming the distribution is normal with a standard deviation of 0.5 hour, approximately what is the meantime, in hours per day, for newborn babies?

A. 15.1
B. 15.3
C. 16.3
D. 16.5
E. 16.7

The Correct Answer and Explanation is:

To find the mean sleep time for newborn babies based on the provided information, let’s carefully analyze the problem:


Given:

  • Sleep time = 15.9 hours/day
  • This sleep time is at the x-th percentile (unknown exact value, but that doesn’t matter because we’re using a normal distribution to back-calculate the mean)
  • Standard deviation (σ) = 0.5 hours
  • The distribution is normal
  • We are asked to find the mean sleep time

Step 1: Understand the relationship

In a normal distribution, any value $X$ can be related to the mean $\mu$ and standard deviation $\sigma$ through the z-score formula:

$$
z = \frac{X – \mu}{\sigma}
$$

We’re told that 15.9 hours is at a certain percentile (though the exact percentile isn’t given, it is implied based on the answer choices). Let’s suppose this value (15.9 hours) corresponds to a certain z-score from the standard normal distribution.


Step 2: Try each answer choice to see which one gives a reasonable z-score

Let’s test each of the mean (μ) values in the choices:

A. μ = 15.1

$$
z = \frac{15.9 – 15.1}{0.5} = \frac{0.8}{0.5} = 1.6
$$

Using a z-table: z = 1.6 corresponds to the 94.52nd percentile

B. μ = 15.3

$$
z = \frac{15.9 – 15.3}{0.5} = 1.2 \rightarrow 88.49th percentile
$$

C. μ = 16.3

$$
z = \frac{15.9 – 16.3}{0.5} = -0.8 \rightarrow 21.19th percentile
$$

D. μ = 16.5

$$
z = \frac{15.9 – 16.5}{0.5} = -1.2 \rightarrow 11.51st percentile
$$

E. μ = 16.7

$$
z = \frac{15.9 – 16.7}{0.5} = -1.6 \rightarrow 5.48th percentile
$$


Step 3: Match percentiles to the value

If 15.9 hours is at the 5th percentile, the correct mean would be 16.7 (choice E).

If 15.9 hours is at the 11th percentile, the mean would be 16.5 (choice D).

The question says: “A sleep time of 15.9 hours/day is at the __ percentile” — meaning we are to find the mean assuming this percentile is accurate.

So, if 15.9 is at the 5.48th percentile, that would imply:

  • $z = -1.6$
  • $\mu = X – z\sigma = 15.9 – (-1.6)(0.5) = 15.9 + 0.8 = 16.7$

Correct Answer: E. 16.7


Conclusion:

This question uses the properties of the normal distribution. By assuming the z-score associated with the given value of 15.9 hours and using the standard deviation, we can work backwards to estimate the mean. When 15.9 hours corresponds to a z-score of -1.6 (which matches the 5.48th percentile), solving the formula yields a mean of 16.7 hours/day. This method is commonly used in statistics to estimate population parameters from percentile data.

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