) Name the first ionic compound and give a formula for the second one: Ti(SO3)2 sulfurous acid c) titanium (II) sulfite: SO, d) tin sulfate; SO a) tantalum (II) sulfate; HSO4 b) titanium (IV) sulfite: H,SO,
The Correct Answer and Explanation is:
Let’s go through the compounds step by step and provide the correct names and formulas along with a 300-word explanation.
Correct Answers:
a) Name: Tantalum(II) hydrogen sulfate
Formula: Ta(HSO₄)₂
b) Name: Titanium(IV) sulfite
Formula: Ti(SO₃)₂
c) Name: Titanium(II) sulfite
Formula: TiSO₃
d) Name: Tin(IV) sulfate
Formula: Sn(SO₄)₂
Explanation
Naming and writing formulas for ionic compounds involve understanding the charges (oxidation states) of the cations and anions involved.
1. Tantalum(II) hydrogen sulfate: Ta(HSO₄)₂
Tantalum (Ta) is a transition metal, and the Roman numeral (II) shows its +2 oxidation state. Hydrogen sulfate (HSO₄⁻) is a polyatomic anion with a −1 charge. To balance the +2 charge of Ta²⁺, two HSO₄⁻ ions are needed, resulting in the formula Ta(HSO₄)₂.
2. Titanium(IV) sulfite: Ti(SO₃)₂
Titanium(IV) means Ti has a +4 charge. The sulfite ion (SO₃²⁻) has a −2 charge. Two sulfite ions (2 × −2 = −4) are needed to balance one Ti⁴⁺ ion. Thus, the formula is Ti(SO₃)₂.
3. Titanium(II) sulfite: TiSO₃
Titanium(II) indicates a +2 charge (Ti²⁺). Sulfite (SO₃²⁻) also has a −2 charge. Since both ions have charges of equal magnitude but opposite sign, only one of each is needed, leading to TiSO₃.
4. Tin(IV) sulfate: Sn(SO₄)₂
Tin(IV) (Sn⁴⁺) and sulfate (SO₄²⁻) combine such that two sulfate ions are required to balance the +4 charge of one Sn⁴⁺ ion (2 × −2 = −4). Hence, the correct formula is Sn(SO₄)₂.
This naming system follows IUPAC rules where transition metals require Roman numerals to indicate their oxidation states. Polyatomic ions like sulfate (SO₄²⁻), sulfite (SO₃²⁻), and hydrogen sulfate (HSO₄⁻) retain their names and are not changed to “-ide.” Matching charges ensures that the compound is electrically neutral.
