Find Each Value Of Za/2. Use A Graphing Calculator And Round The Answers To Three Decimal Places. Part 1 Of 5 (A) Za/2 For The 90% Confidence Interval 2q2 = 1.645 Part: 1/5 Part 2 Of 5 (B) 2/2 For The 97% Confidence Interval 2,2- Undergraduate GPAs It Is Desired To Estimate The Mean GPA Of Each Undergraduate Class At A Large University. How Large A Sample is necessary to estimate the GPA within 0.27 at the 90% confidence level? The population standard deviation is 1.30. If needed, round your final answer up to the next whole number. The university needs at least a sample of students. Cost of Pizzas A pizza shop owner wishes to find the 90% confidence interval of the true mean cost of a large plain pizza. How large should the
Find each value of za/2. Use a graphing calculator and round the answers to three decimal places. Part 1 of 5 (a) Za/2 for th
Undergraduate GPAs It is desired to estimate the mean GPA of each undergraduate class at a large university. How large a sample
Q28;
Using The Divergence Theorem, We Found That The Electric Field Of A Point Charge Of Q Size Q (Or A Uniformly Charged Sphere) Is Given By E(R) = 4.Te,R2 F. Now, Consider Two Point Charges Of Opposite Signs (Or Two Small Charged Spheres) Separated By Distance Ro Along The X-Axis (This Is Called An Electric Dipole): P() V.E() [Q8(R)-Q8(R-Ir)] EO ED A) Explain
The Correct Answer and Explanation is:
Let’s address the two chemistry questions shown in the image regarding electron groups around the central atom:
Part C: CS₂
- Lewis Structure of CS₂: Carbon is the central atom bonded to two sulfur atoms. Each C=S bond is a double bond.
- There are no lone pairs on the central carbon atom.
- Each double bond counts as one electron group.
✅ Answer: 2 electron groups
Part D: CH₄
- Lewis Structure of CH₄: Carbon is the central atom bonded to four hydrogen atoms via single bonds.
- There are no lone pairs on the central carbon atom.
- Each single bond counts as one electron group.
✅ Answer: 4 electron groups
Final Answers:
- Part C (CS₂):
n = 2 - Part D (CH₄):
n = 4
