Draw the structure of 4-bromo-2-iodo-5,6-dimethylnonane: Select Draw More Br Rings
The Correct Answer and Explanation is:
✅ Structure:
CH3
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CH3–CH(I)–CH2–CH(Br)–CH(CH3)–CH(CH3)–CH2–CH2–CH3
🧠 Explanation
The compound 4-bromo-2-iodo-5,6-dimethylnonane is an alkane derived from a straight-chain nonane (9 carbon atoms) backbone, which has been substituted with various groups. Here’s how to interpret and draw it step by step:
1. Base Chain – Nonane:
The parent hydrocarbon is nonane, a straight-chain alkane with 9 carbon atoms:
CH₃–(CH₂)₇–CH₃
We number the carbon atoms from left to right to ensure the lowest possible numbers for the substituents.
2. Identify the Substituents:
- 2-iodo: An iodine atom is attached to carbon 2.
- 4-bromo: A bromine atom is attached to carbon 4.
- 5,6-dimethyl: Methyl groups (–CH₃) are attached to carbons 5 and 6.
3. Final Structure Summary:
- Start by drawing a straight chain of 9 carbon atoms.
- Number the carbon atoms from left to right (1 → 9).
- Add:
- Iodine (I) to carbon 2
- Bromine (Br) to carbon 4
- Methyl (CH₃) to carbon 5
- Methyl (CH₃) to carbon 6
This results in a branched alkane with two halogens and two methyl groups. All substituents must be clearly attached to the correct carbon atoms on the nonane backbone, maintaining the tetrahedral geometry typical of sp³-hybridized carbon atoms.
4. Naming Logic:
The name follows IUPAC rules:
- Longest carbon chain: nonane
- Substituents: listed alphabetically (bromo < iodo < methyl)
- Positions are chosen to give substituents the lowest set of locants.
Thus, the name 4-bromo-2-iodo-5,6-dimethylnonane precisely describes the structure.
