Formula of sodium metaaluminate, sodium stannite, and sodium zincate by Crisscross method. Please answer quickly
The Correct Answer and Explanation is:
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Formulas Using the Crisscross Method
- Sodium metaaluminate: NaAlO₂
- Sodium stannite: Na₂SnO₂
- Sodium zincate: Na₂ZnO₂
Explanation
The Crisscross method is a quick technique to determine the chemical formula of ionic compounds. It involves using the charges (oxidation states) of ions and swapping them to balance the compound’s overall charge.
1. Sodium metaaluminate (NaAlO₂)
- Ions involved:
- Sodium ion: Na⁺ (charge +1)
- Metaaluminate ion: AlO₂⁻ (charge -1)
Since both ions have charges of equal magnitude and opposite sign, we just combine them in a 1:1 ratio:
→ Na⁺ + AlO₂⁻ → NaAlO₂
2. Sodium stannite (Na₂SnO₂)
- Ions involved:
- Sodium ion: Na⁺ (charge +1)
- Stannite ion: SnO₂²⁻ (charge -2)
Apply the crisscross method:
- The charge on sodium (1⁺) becomes the subscript of SnO₂
- The charge on stannite (2⁻) becomes the subscript of Na
→ Na⁺ + SnO₂²⁻ → Na₂SnO₂
This balances the +2 charge from 2 Na⁺ with the –2 charge of one SnO₂²⁻.
3. Sodium zincate (Na₂ZnO₂)
- Ions involved:
- Sodium ion: Na⁺ (charge +1)
- Zincate ion: ZnO₂²⁻ (charge -2)
Apply the crisscross method again:
- The 1⁺ from Na becomes subscript for ZnO₂
- The 2⁻ from ZnO₂ becomes subscript for Na
→ Na⁺ + ZnO₂²⁻ → Na₂ZnO₂
Summary:
The crisscross method ensures the total positive and negative charges cancel each other out, giving a neutral compound. These formulas represent common forms of the oxyanions bonded with sodium in basic or industrial chemistry.
