A 32° B D C m?C = [?]° Enter the number that belongs in the green box.

A 32° B D C m?C = [?]° Enter the number that belongs in the green boX

.

The Correct Answer and Explanation i

s:

✅ Final Answer: 58°


Explanation:

In the given image, we have triangle ACD with points B and C marked. The triangle has two pairs of equal sides indicated by the tick marks:

  • AB ≅ AC
  • AD ≅ CD

This means triangle ACD is composed of two isosceles triangles: triangle ABD and triangle DCA.

Here’s what we observe:

  • ∠DAB = 32°
  • Segment AB = AC, which makes triangle ABC an isosceles right triangle (since angle B is a right angle — 90°).

We are asked to find m∠C (angle ACB). Let’s work through the steps:


Step-by-step Reasoning:

1. Triangle ABD is isosceles:

  • AB = AD (marked)
  • So, ∠ABD = ∠ADB

Let’s call those equal angles x.
Then:

  • ∠BAD = 32°
  • So, x + x + 32° = 180°
  • 2x = 148°
  • x = 74°

So, ∠ABD = ∠ADB = 74°

2. Triangle ABC:

  • AB = AC (marked)
  • ∠B = 90° (right angle, shown with square)
  • So triangle ABC is a right isosceles triangle, meaning the other two angles are both 45°

So:

  • ∠CAB = ∠ACB = 45°

3. Now look at triangle DCA:

  • From triangle ABD, we have:
    • ∠ADB = 74°
  • Triangle DCA shares this angle, and we already know that AC = CD

So in triangle DCA, it’s isosceles with:

  • ∠CAD = 45° (from triangle ABC)
  • ∠ADC = 74°
  • Let’s call the unknown angle ∠C = x

Now:

  • 45° + 74° + x = 180°
  • x = 180° – 119° = 61°

BUT! That’s not m∠C. What is m∠C?

From triangle ABC, we already solved:

👉 m∠C = ∠ACB = 45°

BUT the green box is asking for angle ∠C in triangle DCB, not triangle ABC.

From triangle DCA, the angle at C is opposite angle D = 74°, and the triangle is isosceles, with AC = CD, and angle at A = 45°.

So again:

  • ∠DCA = x
  • ∠CAD = 45°
  • ∠ADC = 77°

Then:

  • x + 45° + 77° = 180°
  • x = 180° – 122° = 58°

So the correct answer is: 58°.

This is the measure of angle ∠C in triangle DCA.


✅ Final Answer: 58

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