Hi, Amount produced, Molar Mass, Molar Mass of Molybdenum, Hi Molybdenum, 10.75 Molar Mass, amount of Molybdenum, grams of Molybdenum, 1, 1.

Hi, Amount produced, Molar Mass, Molar Mass of Molybdenum, Hi Molybdenum, 10.75 Molar Mass, amount of Molybdenum, grams of Molybdenum, 1, 1.

The Correct Answer and Explanation is:

Possible Interpreted Question:

If 10.75 grams of a compound contains molybdenum (Mo), and the molar mass of molybdenum is approximately 95.95 g/mol, how many moles of molybdenum are present?


✅ Correct Answer:

Moles of Mo=Mass of MoMolar Mass of Mo=10.75 g95.95 g/mol≈0.1120 mol\text{Moles of Mo} = \frac{\text{Mass of Mo}}{\text{Molar Mass of Mo}} = \frac{10.75\ \text{g}}{95.95\ \text{g/mol}} \approx 0.1120\ \text{mol}Moles of Mo=Molar Mass of MoMass of Mo​=95.95 g/mol10.75 g​≈0.1120 mol


🧪 Explanation (300 words):

Molar mass is a fundamental concept in chemistry that links the mass of a substance to the number of particles it contains, using Avogadro’s number. The molar mass of molybdenum (Mo) is approximately 95.95 grams per mole (g/mol), meaning one mole of molybdenum atoms weighs 95.95 grams.

When you are given a mass of molybdenum—in this case, 10.75 grams—you can calculate how many moles are present using the formula:Moles=Given Mass (g)Molar Mass (g/mol)\text{Moles} = \frac{\text{Given Mass (g)}}{\text{Molar Mass (g/mol)}}Moles=Molar Mass (g/mol)Given Mass (g)​

By dividing the given mass (10.75 g) by the molar mass (95.95 g/mol), we find that there are approximately 0.1120 moles of molybdenum. This result tells us how many molybdenum atoms we have in terms of moles—a unit that represents 6.022 × 10²³ atoms per mole.

This kind of conversion is essential in stoichiometry, which involves calculating reactants and products in chemical reactions. For instance, if molybdenum is used in the synthesis of an alloy or a compound, knowing the amount in moles allows chemists to determine how much of other substances will be needed or produced in the reaction based on mole ratios from a balanced chemical equation.

Understanding how to convert between mass and moles ensures accurate preparation of substances in laboratories and industrial settings. It’s especially important in fields like materials science, where molybdenum is used in high-strength steel and catalysts.

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