Draw the following alcohols. Then draw the major product from the dehydration of them. 2-methylcyclopentanol 2-methyl-3-pentanol 1-pentanol 2,2-dimethyl-3- pentanol 2. Draw the products when the following alkenes are hydrogenated (reduced). 1-pentene cis-2-hexene 3-methyl-1-butene 3-ethylcyclopentene 3. a) Is the conversion of 1,3-cyclohexadiene to benzene an oxidation or a reduction? b) Is the conversion of 1,3-cyclohexadiene to cyclohexane an oxidation or a reduction? 4. Draw the following alcohols. Classify them as 1º, 2º, or 3°. Finally draw the products when they are oxidized (or no reaction) 2-butanol 3-methyl-1-butanol 2-methyl-1- 1,4-dimethylcyclohexanol cyclopentanol 5. Draw the products when the following carbonyl compounds are reduced. 2-pentanone 2-3-dimethylbutanal 3-methylcyclohexanone 3,3-dimethyl-2- butanone
The Correct Answer and Explanation is:
Here are the completed answers for the worksheet, followed by a detailed explanation of the chemical principles involved.
-1-cyclopentanol (2°):** This is a 2° alcohol (the carbinol carbon is bonded to two other ring carbons), so it oxidizes to the ketone 2-methylcyclopentanone.
- 1,4-dimethylcyclohexanol (3°): This is a 3° alcohol, so there is no reaction.
5. Reduction of Carbonyl Compounds
Carbonyl compounds (aldehydes and ketones) are reduced to alcohols using reagents like sodium borohydride (NaBH₄) or lithium aluminum hydride (LiAlH₄). Aldehydes are reduced to primary (1°) alcohols, and ketones are reduced to secondary (2°) alcohols.
- 2-pentanone (ketone): Reduces to the 2° alcohol 2-pentanol.
- 2,3-dimethylbutanal (aldehyde): Reduces to the 1° alcohol 2,3-dimethyl-1-butanol.
- 3-methylcyclohexanone (ketone): Reduces to the 2° alcohol 3-methylcyclohexanol.
- 3,3-dimethyl-2-butanone (ketone): Reduces to the 
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