What is the output of the following cod O py Oyn O pyn O yna

str = “pynative” print (str[1:3]) What is the output of the following cod O py Oyn O pyn O yna
str = “pynative” print (str[1:3]) What is the output of the following cod O py Oyn O pyn O yna

The Correct Answer and Explanation is:

Correct Answer: yn

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Explanation:

In the given code:

pythonCopyEditstr = "pynative"
print(str[1:3])

We are using string slicing, which allows you to extract a part of the string using the syntax:
string[start_index : end_index]

This extracts characters starting from the position start_index up to but not including end_index.

Step-by-step breakdown:

1. The original string is: iniCopyEditstr = "pynative" The characters in the string have the following index positions: makefileCopyEditIndex: 0 1 2 3 4 5 6 7 Character: p y n a t i v e
2. Now let’s examine the slicing: pythonCopyEditstr[1:3]
   • 1 is the starting index, which corresponds to the character ‘y’
   • 3 is the ending index, but it is not included in the result
   • So this slice includes the characters at index 1 and 2 only
3. Characters at these positions:
   • Index 1: 'y'
   • Index 2: 'n'
4. Therefore, str[1:3] gives us: 'yn'

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Why other choices are incorrect:

• py: would require str[0:2]
• pyn: would require str[0:3]
• yna: would require str[1:4]

Only ‘yn’ is the correct output for str[1:3].

This concept is important when working with lists, strings, or any sequence in Python, as slicing is a powerful and efficient way to manipulate data. Understanding that the end index is excluded helps avoid common off-by-one errors in your programs.