create a lewis dot structure for CuS
The correct answer and explanation is:
The compound CuS (copper(II) sulfide) consists of copper (Cu) and sulfur (S). To create a Lewis dot structure, we need to consider the bonding between the atoms and the valence electrons.
Step 1: Determine the valence electrons.
- Copper (Cu) is in Group 11 of the periodic table, so it has 1 valence electron.
- Sulfur (S) is in Group 16, so it has 6 valence electrons.
Step 2: Determine the bonding.
- Copper typically forms a 2+ ion (Cu²⁺), which means it loses 2 electrons. Therefore, it will not have any lone pairs in the Lewis structure.
- Sulfur, on the other hand, typically gains 2 electrons to form a 2- ion (S²⁻), resulting in a full octet.
Step 3: Form the structure.
- Copper (Cu) and sulfur (S) are connected by an ionic bond in CuS. Copper donates its 2 valence electrons to sulfur, forming a Cu²⁺ ion and an S²⁻ ion.
- The resulting structure is ionic, and since it is an ionic compound, there are no shared electron pairs between the atoms. Instead, the Cu²⁺ and S²⁻ ions are held together by electrostatic forces.
Lewis Dot Structure:
- Copper (Cu) does not have any dots, as it loses its valence electrons to become Cu²⁺.
- Sulfur (S) will have 6 valence electrons, but after accepting 2 electrons, it will be surrounded by 8 electrons in its valence shell, represented by dots.
The ionic bond between Cu²⁺ and S²⁻ is depicted as:
Cu²⁺ [S²⁻]
This structure shows the electron transfer between copper and sulfur, with copper losing two electrons and sulfur gaining them. The result is the formation of Cu²⁺ and S²⁻ ions, which are held together in the solid by ionic forces.