What is the formula for copper (II) chlorate Preview What is the molar mass of copper (II) chlorate g/mole How many moles are there in 174.7 g of copper (II) chlorate moles How many grams are there in 2.5 moles of copper (II) chlorate g
The Correct Answer and Explanation is:
Formula for Copper (II) Chlorate:
The formula for copper (II) chlorate is Cu(ClO3)2.
Molar Mass of Copper (II) Chlorate:
To calculate the molar mass of Cu(ClO3)2, we need to sum up the atomic masses of all the atoms in the formula:
- Copper (Cu) has an atomic mass of 63.55 g/mol.
- Chlorine (Cl) has an atomic mass of 35.45 g/mol.
- Oxygen (O) has an atomic mass of 16.00 g/mol.
Now, let’s calculate the molar mass:
- 1 Cu atom = 63.55 g/mol
- 2 Cl atoms = 2 × 35.45 g/mol = 70.90 g/mol
- 6 O atoms (since there are 3 O atoms in each ClO3 group and there are 2 such groups) = 6 × 16.00 g/mol = 96.00 g/mol
Thus, the molar mass of Cu(ClO3)2 is:
63.55+70.90+96.00=230.45 g/mol63.55 + 70.90 + 96.00 = 230.45 \, \text{g/mol}63.55+70.90+96.00=230.45g/mol
Moles in 174.7 g of Copper (II) Chlorate:
To find the number of moles, we use the formula:moles=massmolar mass\text{moles} = \frac{\text{mass}}{\text{molar mass}}moles=molar massmass
Substitute the given values:moles=174.7 g230.45 g/mol=0.758 moles\text{moles} = \frac{174.7 \, \text{g}}{230.45 \, \text{g/mol}} = 0.758 \, \text{moles}moles=230.45g/mol174.7g=0.758moles
Grams in 2.5 Moles of Copper (II) Chlorate:
To find the mass in grams for 2.5 moles, we use the formula:mass=moles×molar mass\text{mass} = \text{moles} \times \text{molar mass}mass=moles×molar mass
Substitute the given values:mass=2.5 moles×230.45 g/mol=576.125 g\text{mass} = 2.5 \, \text{moles} \times 230.45 \, \text{g/mol} = 576.125 \, \text{g}mass=2.5moles×230.45g/mol=576.125g
Thus, the answers are:
- The molar mass of copper (II) chlorate is 230.45 g/mol.
- There are 0.758 moles in 174.7 g of copper (II) chlorate.
- There are 576.13 grams in 2.5 moles of copper (II) chlorate.
