Khan Academy Active Past Basic multi-digit division 87 \div 17 = \text{ remainder }
The Correct Answer and Explanation is:
Of course. Here is the solution to the math problem shown in the image, along with a detailed explanation.
Correct Answer:
87 ÷ 17 = 5 remainder 2
Explanation
The problem asks us to solve the division 87 ÷ 17 and find the whole number quotient and the remainder. This is a “basic multi-digit division” problem, which means we need to determine how many times the divisor (17) can fit into the dividend (87) completely, and what is left over.
Step 1: Understand the Goal
Our objective is to find two numbers:
- The Quotient: The whole number result of the division.
- The Remainder: The amount left over after the division is complete. The remainder must always be smaller than the divisor.
Step 2: Estimate the Quotient
We need to find out how many times 17 goes into 87. We can do this by estimating or by listing multiples of the divisor, 17.
Let’s list the multiples of 17:
- 17 × 1 = 17
- 17 × 2 = 34
- 17 × 3 = 51
- 17 × 4 = 68
- 17 × 5 = 85
- 17 × 6 = 102
Looking at this list, we can see that 17 × 5 equals 85, which is the largest multiple of 17 that is less than our dividend, 87. The next multiple, 17 × 6, is 102, which is too large. Therefore, 17 fits into 87 a total of 5 whole times. This means our quotient is 5.
Step 3: Calculate the Remainder
Now that we know the quotient is 5, we can find out what is left over. We multiply our quotient (5) by our divisor (17) to see how much of the dividend has been accounted for.
5 × 17 = 85
Next, we subtract this result from the original dividend (87) to find the remainder.
87 – 85 = 2
The amount left over is 2. This is our remainder. We can also check that the remainder (2) is smaller than the divisor (17), which confirms our calculation is correct.
Step 4: State the Final Answer
By combining the quotient and the remainder, we can state the complete solution to the problem.
87 divided by 17 is 5 with a remainder of 2
