Determine the Lewis & VSEPR structure for ClO2F and determine if the molecule is polar

Determine the Lewis & VSEPR structure for ClO2F and determine if the molecule is polar

The Correct Answer and Explanation is:

The molecule ClO2F consists of a chlorine (Cl) atom bonded to two oxygen (O) atoms and one fluorine (F) atom. To determine the Lewis structure, we need to follow these steps:

1. Counting Valence Electrons:

  • Chlorine (Cl) is in Group 17, so it has 7 valence electrons.
  • Oxygen (O) is in Group 16, so each oxygen atom has 6 valence electrons. Since there are two oxygen atoms, we have 12 valence electrons from oxygen.
  • Fluorine (F) is also in Group 17, so it has 7 valence electrons.
    Thus, the total number of valence electrons is:

7(Cl)+12(O)+7(F)=26 valence electrons.7 (\text{Cl}) + 12 (\text{O}) + 7 (\text{F}) = 26 \text{ valence electrons.}7(Cl)+12(O)+7(F)=26 valence electrons.

2. Drawing the Lewis Structure:

  • Chlorine will be the central atom since it is less electronegative than oxygen and fluorine.
  • The two oxygen atoms and one fluorine atom will each form a single bond with chlorine.
  • After the bonds, distribute the remaining electrons to complete the octet of oxygen and fluorine atoms.
  • Chlorine, as a larger atom, will have more than 8 electrons around it in this case, which is allowed.

After arranging the atoms and distributing the electrons, the Lewis structure will look like this:

  • Cl is single-bonded to each oxygen and fluorine.
  • The oxygen atoms will have lone pairs to satisfy their octets.
  • Fluorine will also have lone pairs.

3. VSEPR Structure:

The VSEPR theory helps predict the molecular geometry by considering the regions of electron density around the central atom. In ClO2F, there are three regions of electron density around chlorine: two from the oxygen atoms and one from the fluorine atom.

  • Electron Domain Geometry: Trigonal planar.
  • Molecular Geometry: The three bonded atoms create a trigonal pyramidal shape since the lone pairs on oxygen atoms are not part of the molecular shape.

4. Polarity:

To determine if ClO2F is polar, consider the electronegativity of the atoms and the molecular shape:

  • Chlorine is less electronegative than fluorine but more electronegative than oxygen.
  • The presence of fluorine, which is highly electronegative, creates a region of negative charge near it.
  • The molecule has an asymmetrical shape (trigonal pyramidal), which means the dipoles from the different bonds do not cancel out.

Thus, ClO2F is a polar molecule because of its asymmetrical shape and the differences in electronegativity between the atoms, which result in a net dipole moment.

In summary:

  • Lewis structure: Cl with single bonds to two oxygens and one fluorine, with lone pairs on oxygen and fluorine atoms.
  • VSEPR geometry: Trigonal pyramidal.
  • Polarity: The molecule is polar due to its asymmetric shape and electronegativity differences.
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