Be sure to answer all parts. Write a balanced equation for each reaction. a. HBr(aq) + KOH(aq) ? HBr (aq) +KOH (aq) KBR (aq) +H2O (l) Feedback Examine your products. In a neutralization reaction, water and an ionic salt are formed. Is your ionic compound charge balanced? Did you balance the equation and include the states of each substance? Ok, got it
The Correct Answer and Explanation is:
The reaction between hydrobromic acid (HBr) and potassium hydroxide (KOH) is a neutralization reaction. In a neutralization reaction, an acid reacts with a base to form water and an ionic salt. The reaction between HBr and KOH is no exception.
Step 1: Write the reactants.
- HBr is a strong acid, and in aqueous form, it dissociates completely into H+H^+H+ and Br−Br^-Br− ions.
- KOH is a strong base, and in aqueous form, it dissociates completely into K+K^+K+ and OH−OH^-OH− ions.
Step 2: Predict the products.
When these ions combine in the neutralization reaction:
- H+H^+H+ from HBr reacts with OH−OH^-OH− from KOH to form water H2OH_2OH2O.
- The remaining ions K+K^+K+ and Br−Br^-Br− combine to form the ionic salt potassium bromide (KBr), which is soluble in water.
Step 3: Write the equation for the reaction.
The balanced equation is:HBr (aq)+KOH (aq)→KBr (aq)+H2O (l)\text{HBr (aq)} + \text{KOH (aq)} \rightarrow \text{KBr (aq)} + \text{H}_2\text{O (l)}HBr (aq)+KOH (aq)→KBr (aq)+H2O (l)
Step 4: Check charge balance.
- On the left side of the equation, the ions are H+H^+H+, Br−Br^-Br−, K+K^+K+, and OH−OH^-OH−, which are all neutralized by the right side of the equation.
- On the right, potassium bromide (KBr) dissociates into K+K^+K+ and Br−Br^-Br−, and water (H₂O) is neutral, balancing the charges.
Step 5: States of matter.
- HBr and KOH are both aqueous (aqaqaq), meaning they are dissolved in water.
- KBr is also aqueous (aqaqaq) because it is soluble in water.
- Water is a liquid (lll) at room temperature.
Final balanced equation:
HBr (aq)+KOH (aq)→KBr (aq)+H2O (l)\text{HBr (aq)} + \text{KOH (aq)} \rightarrow \text{KBr (aq)} + \text{H}_2\text{O (l)}HBr (aq)+KOH (aq)→KBr (aq)+H2O (l)
This equation is now balanced in terms of both mass and charge, and the states of matter are correctly indicated.
